y = 3x + 5
Let x = one number = 2 or 2.5 Let y = the other number = 2.5 or 2 (x)(y)=5 x+y=4.5 y=4.5-x (x)(y)=5 (x)(4.5-x)=5 4.5x-x^2-5=0 I used the quadratic formula to get x. x=2 or x=2.5 (x)(y)=5 (2)(y)=5 y=5/2 y=2.5 (x)(y)=5 (2.5)(y)=5 y=5/2.5 y=2
x^(4)*y*x^(5)*yMultiply x^(4) by y to get x^(4)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(4)y*x^(5)*yMultiply x^(4)y by x^(5) to get x^(9)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y*yMultiply x^(9)y by y to get x^(9)y^(2).(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y^(2)To find the derivative of x^(9)y^(2), multiply the base (x) by the exponent (9), then subtract 1 from the exponent.(d)/(dx) x^(4)*y*x^(5)*y=9x^(8)y^(2)The derivative of x^(4)*y*x^(5)*y is 9x^(8)y^(2).9x^(8)y^(2)
No. In the variable x, alone, it is linear. In the variable y, alone, it is linear. But taken together, in x and y, you have a term which contains xy - that is, a term in which the powers of the unknowns add to 2. So the equation is not linear.
The inverse of a linear function is always a linear function. There are a few ways to approach this.To think about it, you can imagine flipping the x and y axes. Essentially this equates to turning the graph of the linear function on its side to reveal the new inverse function which is still a straight line.More rigorously, the linear function y = ax + b has the inverse equation x = (1/a)y - (b/a). This is a linear function in y.
Definitely linear In straight line form it is 5y = 2x + 10 y = (2/5)x + 10/5 y = (2/5)x + 2
If you already know that x = -3 and y = 5 what linear equations are you wanting to solve?
Yes.
I your highest power of your variables is 1 then it is linear. y=x+5 is linear
No, to be linear, both the power of x and y need to be 1. Since x is squared, the power of x is 2.
x + y = 0 x + y = 1 x + y = 2 x + y = 3 x + y = 4
If you mean: y-3 = 4(x+5) then y = 4x+23
Sure. for y = mx + b, with m = (1/5), you would have y = x/5 + b. The slope is 1/5.
y = 3x + 5
Yes, y = 3+x is linear.
y=x-5 is a linear equation that has been shifted down 5, the slope is still 1. So if you plug in points for x, you can find the position easily. When x=0, y=-5. When x=1, y=-4. And when x=-1, y=-6.
3x = 5y3x/5 = 5y/5(3/5)x = y ory = (3/5)x + 0 is a linear equation of the form y = mx + b, where the slope, m, is 3/5, and the y-intercept, b, is 0.