8.8 Units
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Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).
Given a straight line joining the points A and B, the perpendicular bisector is a straight line that passes through the mid-point of AB and is perpendicular to AB.
answerDraw two lines of equal lengths perpendicular to AB on the same side of AB and extend the line formed by joining the two end points of the two perpendicular lines which does not line on the line AB.
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
Using the distance formula the length of ab is 5 units