Pipe 1: 0,5 tanks per hour (2 hours to fill)
Pipe 2: 0,2 tanks per hour (5 hours to fill)
If we let X be the time in hours to fill the tank:
0,5 * X + 0,2 * X = 1 (one tank filling)
0,7 * X = 1
X = 1 ÷ 0,7 = 1.428571429... ≈ 1.43 hours or almost 1 hour 26 minutes
10 2/7 hours
4hr.
Pump 'A' can fill 1/6 of the tank in one hour. 1/6 is the same as 2/12 Pump 'B' can drain 1/12 of the tank in one hour. If both pumps are running at the same time, then in one hour 2/12 get filled and 1/12 gets drained, and the net effect is 1/12 getting filled in that hour. If the tank is initially empty and both pumps start at the same time, then the tank will fill in 12 hours. *edit* It takes six hours if pump B is left off.
addresses the demand.
supply, provide, furnish
10 2/7 hours
4hr.
If 7 pipes can fill a water tank in 6 hours, then 1 pipe would take 7 times 6 or 42 hours. Take 42 and divide by 9, and you get 4 2/3 hours. That is the time it would take for 9 pipes to fill the tank.
wellto answer it we'll have to kno how much the fountain can hold . plz restate your question :)
Pipe A fills 1/12 of the tank per hour, and Pipe B fills 1/8 of the tank per hour. Together, they fill 1/12+1/8 of the tank per hour. 1/12+1/8=(1*8)/(12*8)+(1*12)/(12*8)=(8+12)/(12*8)=20/96=5/24 of the tank per hour So, it would take 1/(5/24)=24/5 = 4.8 hours to fill the tank with both pipes.
In one hour first pipe fills 1/7th of pool, other pipe fills one-half, so together in one hour they fill 1/7 + 1/2 ie 9/14 so would take 14/9 hours (93 and a third minutes) to fill the pool. ie 1 hr 33 min 20 sec
The reciprocal of the added reciprocals. 1/T = 1/A + 1/B + ... 1/Z In your case: 1/T = 1/5 + 1/2 +1/6 1/T = 6/30 + 15/30 + 5/30 1/T = 26/30 T = 30/26 = 15/13 hours = 1 hour 9 minutes 14 seconds
pipe a fill 1/4th part in 7 mins and pipe b in 7.5 mins hence both tank will fill 1/4th of tank in 7+7.5/4 = 3.6 mins
replace the fill valve
It would take the too pipes 30 minutes to fill the tank when working together.This figure can be found in the following manner:Find the fill-speed of the first pipe50 minutes to fill 6000 Liters. 6000L/50m gives us 120L/m (liters-per-minute)6000 Liters in 75 minutes = 6000L/75m = 80L/mNext find the speed of the second pipeNow we combine the two rates (120+80), and we find that the pipes have a combined fill-speed of 200L/mFinally, we determine that it takes 30 minutes to fill the tank at 200L/m
Assuming the flow rate is constant (in a real system, this probably will not be the case, at least for the drain; it probably drains faster when nearly full than when nearly empty), then for convenience sake let's say the pool holds six units of water. It fills at 2 units per hour and drains at 1 unit per hour. If both pipes are open, the net gain is 1 unit per hour, so it will fill in six hours (and then start overflowing unless both pipes are shut off).
If that's 25%, it will fill in four hours. If that's 2/5 (40%), it will fill in 2.5 hours.