It helps to convert everything to cosines, using the Pythagorean formula, i.e., sin2x + cos2x = 1.
sin2x + cos x = 0
(1 - cos2x) + cos x = 0
-cos2x + cos x + 1 = 0
cos2x - cos x - 1 = 0
Now you can apply the quadratic formula, solving for cos x, and using a = 1, b = -1, c = -1.
It helps to convert everything to cosines, using the Pythagorean formula, i.e., sin2x + cos2x = 1.
sin2x + cos x = 0
(1 - cos2x) + cos x = 0
-cos2x + cos x + 1 = 0
cos2x - cos x - 1 = 0
Now you can apply the quadratic formula, solving for cos x, and using a = 1, b = -1, c = -1.
It helps to convert everything to cosines, using the Pythagorean formula, i.e., sin2x + cos2x = 1.
sin2x + cos x = 0
(1 - cos2x) + cos x = 0
-cos2x + cos x + 1 = 0
cos2x - cos x - 1 = 0
Now you can apply the quadratic formula, solving for cos x, and using a = 1, b = -1, c = -1.
It helps to convert everything to cosines, using the Pythagorean formula, i.e., sin2x + cos2x = 1.
sin2x + cos x = 0
(1 - cos2x) + cos x = 0
-cos2x + cos x + 1 = 0
cos2x - cos x - 1 = 0
Now you can apply the quadratic formula, solving for cos x, and using a = 1, b = -1, c = -1.
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It helps to convert everything to cosines, using the Pythagorean formula, i.e., sin2x + cos2x = 1.
sin2x + cos x = 0
(1 - cos2x) + cos x = 0
-cos2x + cos x + 1 = 0
cos2x - cos x - 1 = 0
Now you can apply the quadratic formula, solving for cos x, and using a = 1, b = -1, c = -1.
you need this identities to solve the problem..that is something you have to memorized sec x= 1/cosx 1-cos2x= sin2x tanx= sin x/cosx also, sin 2x= (sinx)(sinx) sec x - cosx= sin x tanx (1/cosx)-cosx= sin x tanx .. 1-cos2x / cosx=sin x tanx sin2x/ cosx= sin x tanx (sin x/cox)( sin x)= sin x tanx tanx sinx= sin x tanx
cosx^2 differentiates too 2(cosx)^1 x the differential of cos which is -sin so u get -2sinxcosx use the chain rule!
d/dx(sinx-cosx)=cosx--sinx=cosx+sinx
cosx * tanx = sinx cos x . sin x/ cosx = sinx cos x . sin x/cosx = sinx (cos x is taken out of the equation, leaving sin x = sin x).
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