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# Sin squared x pluss cosx equals 0?

Wiki User

2009-11-26 11:37:10

It helps to convert everything to cosines, using the Pythagorean formula, i.e., sin2x + cos2x = 1.

sin2x + cos x = 0

(1 - cos2x) + cos x = 0

-cos2x + cos x + 1 = 0

cos2x - cos x - 1 = 0

Now you can apply the quadratic formula, solving for cos x, and using a = 1, b = -1, c = -1.

It helps to convert everything to cosines, using the Pythagorean formula, i.e., sin2x + cos2x = 1.

sin2x + cos x = 0

(1 - cos2x) + cos x = 0

-cos2x + cos x + 1 = 0

cos2x - cos x - 1 = 0

Now you can apply the quadratic formula, solving for cos x, and using a = 1, b = -1, c = -1.

It helps to convert everything to cosines, using the Pythagorean formula, i.e., sin2x + cos2x = 1.

sin2x + cos x = 0

(1 - cos2x) + cos x = 0

-cos2x + cos x + 1 = 0

cos2x - cos x - 1 = 0

Now you can apply the quadratic formula, solving for cos x, and using a = 1, b = -1, c = -1.

It helps to convert everything to cosines, using the Pythagorean formula, i.e., sin2x + cos2x = 1.

sin2x + cos x = 0

(1 - cos2x) + cos x = 0

-cos2x + cos x + 1 = 0

cos2x - cos x - 1 = 0

Now you can apply the quadratic formula, solving for cos x, and using a = 1, b = -1, c = -1.

Wiki User

2009-11-26 11:37:10
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## A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Wiki User

2009-11-26 11:37:10

It helps to convert everything to cosines, using the Pythagorean formula, i.e., sin2x + cos2x = 1.

sin2x + cos x = 0

(1 - cos2x) + cos x = 0

-cos2x + cos x + 1 = 0

cos2x - cos x - 1 = 0

Now you can apply the quadratic formula, solving for cos x, and using a = 1, b = -1, c = -1.