answersLogoWhite

0


Best Answer

(1+cosx)(1-cosx)= 1 +cosx - cosx -cos^2x (where ^2 means squared)

= 1-cos^2x = sin^2x (sin squared x)

User Avatar

Wiki User

9y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

9y ago

[1 + cos(x)]*[(1 - cos(x)] = 1 - cos^2(x) = sin^2(x)

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is (1 plus cos x)(1- cos x)?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How do you solve sinx divided by 1 plus cosx plus cosx divided by sinx?

sin x/(1+cos x) + cos x / sin x Multiply by sin x (1+cos x) =[(sin^2 x + cos x(1+cos x) ] / sin x (1+cos x) = [(sin^2 x + cos x + cos^2 x) ] / sin x (1+cos x) sin^2 x + cos^2 x = 1 = (1+cos x) / sin x (1+cos x) = 1/sin x


How do you prove that (1 plus cotx)2-2cotx 1(1-cos)(1 plus cos)?

Manipulate normally, noting:cot x = cos x / sin xcos² x + sin² x = 1 → sin²x = 1 - cos² xa² - b² = (a + b)(a - b)1 = 1²ab = baa/(bc) = a/b/c(1 + cot x)² - 2 cot x = 1² + 2 cot x + cot² x - 2 cot x= 1 + cot² x= 1 + (cos x / sin x)²= 1 + cos² x / sin² x= 1 + cos² x / (1 - cos² x)= ((1 - cos² x) + cos² x)/(1 - cos² x)= 1/(1² - cos² x)= 1/((1 + cos x)(1 - cos x))= 1/(1 - cos x)/(1 + cos x)QED.


2 cos x plus 1 cos x plus -1 equals 0?

2 cos * cos * -1 = 2cos(square) * -1 =cos(square) + cos(square) *-1 =1- sin(square) +cos(square) * -1 1 - 1 * -1 =0


Cos x equals -cos x plus 1?

No, but cos(-x) = cos(x), because the cosine function is an even function.


What is X3 plus X2 plus X plus 1 divided by X 1?

2x2+7/x1


How does sin2x divided by 1-cosx equal 1 plus cosx?

sin2x / (1-cos x) = (1-cos2x) / (1-cos x) = (1-cos x)(1+cos x) / (1-cos x) = (1+cos x) sin2x=1-cos2x as sin2x+cos2x=1 1-cos2x = (1-cos x)(1+cos x) as a2-b2=(a-b)(a+b)


Prove identity cos 2xcot2 x-1cot2 x1?

the questions is 2x=(cot^2 x-1)/(cot^2 x+1)


What is the integral of 1 divided by sin x plus cos x?

The question is ambiguous: does it refer to 1/sin(x) + cos(x) or to 1/[sin(x)+cos(x)]?The question is ambiguous: does it refer to 1/sin(x) + cos(x) or to 1/[sin(x)+cos(x)]?The question is ambiguous: does it refer to 1/sin(x) + cos(x) or to 1/[sin(x)+cos(x)]?The question is ambiguous: does it refer to 1/sin(x) + cos(x) or to 1/[sin(x)+cos(x)]?


What is the limit as x approaches 0 of 1 plus cos squared x over cos x?

2


How do you express sin x plus cos x divided by cos x in terms of tan x?

(sin x + cos x) / cosx = sin x / cos x + cosx / cos x = tan x + 1


What is the solution to cos x equals 3 cos x - 2?

1


Is 1- cos 2 x 1 plus cos 2 x equals sin squared x cos squared x an identity?

No, (sinx)^2 + (cosx)^2=1 is though