sum
a-d+a+a+d=36
3a=36
a=12
product=1296
(a-d)a(a+d)=1296
(a^2 -d^2)a=1296.......now put a=12
144-d^2=108
36=d^2
d=+ or - 6
taking +,we get 6,12,18
taking -,we get 18,12,6
FINAL ASWER 6,12,18
BY FRANCIS NTI-FRIMPONG
4
The product is the result of a multiplication sum. Since this sum has just one number in the question part, it is impossible to find the product of this single number.
They are all mathematical terms."sum" can be used to mean any arithmetical calculation.However, the terms come in pairs to mean the results of inverse operations:difference is used to denote the result of a subtraction and sum is used to denote the result of an addition;quotient is used to denote the result of a division and product is used to denote the result of a multiplication
19
29.
To get the product, multiply the first number by the second. To get the sum, add the second number to the first. To get the difference, subtract the smaller number from the larger.
1,944 = 1296 x 1.5
7 terms
To solve the sum and difference of two terms, you can use the identities for the sum and difference of squares. For two terms (a) and (b), the sum is expressed as (a + b) and the difference as (a - b). To find their product, you use the formula: ((a + b)(a - b) = a^2 - b^2). This allows you to calculate the difference of squares directly from the sum and difference of the terms.
The difference.
wala
It is so much easier and so much quicker to get the answer if you use your calculator. 1296 + 3978 = 5274
54 and 16.
No. It is a sum of four terms which can be simplified to a sum of three terms.
12(6 + 5)
To find the probability of rolling a sum of six followed by a sum of eight with two six-sided dice, we first calculate each individual probability. The probability of rolling a sum of six is 5/36, and the probability of rolling a sum of eight is 5/36 as well. Since these events are independent, we multiply the probabilities: (5/36) * (5/36) = 25/1296. Thus, the probability of rolling a sum of six followed by a sum of eight is 25/1296.
No, you cannot always find the sum of the factors of a product just by knowing the product itself. For example, the product 6 can be factored into 2 and 3, which sum to 5. However, it can also be factored into 1 and 6, which sum to 7. Therefore, the sum of the factors varies depending on the specific factorization chosen.