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Let the AP be a-d,a,a+d


sum


a-d+a+a+d=36


3a=36


a=12


product=1296


(a-d)a(a+d)=1296


(a^2 -d^2)a=1296.......now put a=12


144-d^2=108


36=d^2


d=+ or - 6


taking +,we get 6,12,18


taking -,we get 18,12,6


FINAL ASWER 6,12,18


BY FRANCIS NTI-FRIMPONG

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11y ago
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Q: Sum of terms of an AP is 36 and product is 1296 Find AP?
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