Best Answer

n(S)=8

let A be the event that more than one tail appears

n(A)=4

so,P(A)=4\8=0.5

Q: Suppose three coins are tossed what is the probability of tossing more than one tail?

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The probability of tossing two heads in two coins is 0.25.

(0.5)n

The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4

255/256 (complement formula)

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Related questions

If they are fair coins, it is 1/16.

The probability of tossing two heads in two coins is 0.25.

The probability is 1/21/21/2*1/2=1/16, or 0.0625 or 6.25%

The probability of tossing two coins that are different is 1 in 2, or 0.5.The probability of tossing something on the first coin is 1. The probability of not matching that on the second coin is 0.5. Multiply 1 and 0.5 together, and you get 0.5.

the probability is 0.03125 or 3.123%

The probability is 1/16.

25%

7/8

0.1222...

Coins do not have numbers, there is only the probability of heads or tails.

1/4 if they are tossed only once.

The probability is 1/2^4 = 1/16