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First: note 3 things about cot and tan, and note the given statement:

  1. cot = 1/tan
  2. tan is cyclic with a period of π, that is tan(nπ + x) = tan(x)
  3. tan is an odd function, that is tan(-x) = -tan(x)
  4. tan(Ï€/4) = 1

Now apply them to the problem:

  1. cot(π - π/4) = 1/tan(π - π/4)
  2. = 1/tan(-Ï€/4)
  3. = 1/-tan(Ï€/4)
  4. = 1/-1 = -1

Thus:

cot(π - π/4) = -1.

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โˆ™ 2017-05-06 06:57:10
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โˆ™ 2017-05-05 12:19:42

Cot(pi - pi/4) = cot(3*pi/4) = -1

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Q: What is cot of pi - pi over 4 given that tan of pi over 4 equals 1?
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