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First: note 3 things about cot and tan, and note the given statement:
- cot = 1/tan
- tan is cyclic with a period of π, that is tan(nπ + x) = tan(x)
- tan is an odd function, that is tan(-x) = -tan(x)
- tan(Ï€/4) = 1
Now apply them to the problem:
- cot(π - π/4) = 1/tan(π - π/4)
- = 1/tan(-Ï€/4)
- = 1/-tan(Ï€/4)
- = 1/-1 = -1
Thus:
cot(π - π/4) = -1.
What else can I help you with?
What is the cotangent of 65 degrees?
For an angle, ?, the cotangent (or cot) of the angle is given bycot ? = 1/tan ?If ?=65
The function cot 115 degrees is equivalent to?
cot(115º) = -tan(25) or cot(115º) = -0.466308
What is wrong with the following statement tan 90 degrees equals 1 overcot 90 degrees?
Cot(90) = 0 so 1/cot(90), if defined, would be 1/0. Such a fraction is not defined and that is what is wrong with the sentence.
If tansqtheta plus 5tantheta0 find the value of tantheta plus cottheta?
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
What is cot x?
Cot x is 1/tan x or cos x / sin x or +- sqrt cosec^2 x -1
1 over tan x equals what?
1/ Tan = 1/ (Sin/Cos) = Cos/Sin = Cot (Cotangent)
What is the solution to cos tan-sin over cot equals 0?
either cos OR tan-sin equals zero socos=0 at pi/2 and 3pi/2ortan=sin which is impossibleim not sure though
What is the answer to cot squared x - tan squared x equals 0?
cot2x-tan2x=(cot x -tan x)(cot x + tan x) =0 so either cot x - tan x = 0 or cot x + tan x =0 1) cot x = tan x => 1 / tan x = tan x => tan2x = 1 => tan x = 1 ou tan x = -1 x = pi/4 or x = -pi /4 2) cot x + tan x =0 => 1 / tan x = -tan x => tan2x = -1 if you know about complex number then infinity is the solution to this equation, if not there's no solution in real numbers.
Csc divided by cot squared equals tan multiplied by sec?
Yes.
Tan theta plus cot theta equals 2csc2 theta?
Yes, it is.
If tan Theta equals 2 with Theta in Quadrant 3 find cot Theta?
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
Cos2x equals 1 minus tan squared x divide by1 plus tan squared x?
The Answer is 1 coz, 1-Tan squarex = Cot square X. So cot square x divided cot square x is equal to 1
How can you verify 1 plus tan theta divided by 1 minus tan theta equals cot theta plus 1 divided by cot theta minus 1?
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
What is the cotangent of 65 degrees?
For an angle, ?, the cotangent (or cot) of the angle is given bycot ? = 1/tan ?If ?=65
How do you make the left the same as the right for tan 0 times cot 0 all over tan 0 csc2 0?
You cannot because cot(0) is not defined, neither is cosec(0).
How do you simplify tan cot equals 1?
It just simplifies down to 1=1. You have to use your trig identities... tan=sin/cos cot=cos/sin thus tan x cot= (sin/cos) (cos/sin) since sin is in the numerator for tan, when it is multiplied by cot (which has sin in the denominator) both of the signs cancel and both now have a value of 1. The same happens with cos. so you get 1 x 1=1 so there is your answer. just learn your trig identities and you will understand
The function cot 115 degrees is equivalent to?
cot(115º) = -tan(25) or cot(115º) = -0.466308
