As there are two consecutive integers then one must be an even number and the other an odd number. If the numbers are y and y + 1 then if y is even, y + 1 is odd and if y is odd then y + 1 is even.
The product of an even integer and an odd integer is always even.
The question therefore has no answer.
121 = 112 but this is not what the question has asked.
You need at least two numbers to find an LCM. If that's 12 and 11, the LCM of consecutive integers is their product.
They are are 7 and 8.
13 & 15
44 & 45
27 and 28
The numbers are 8 and 9.
9240 is the product of the three consecutive integers 20, 21, and 22.
The numbers are 11, 13, 15 and 17.
4,6,8,10
The product of 2 consecutive positive number is 48. Find the 2 numbers
First, we are not interested for the sign of the numbers, because the product of two negative numbers is always positive, so we need to find the two consecutive factors of 240, which are 15 and 16. Thus, the numbers are -16 and -15.
The two numbers are either 7 and 8 or -7 and -8.
They are 6, 8, 10 and 12.
The numbers are 65 and 67.
You need at least two numbers to find an LCM. If that's 12 and 11, the LCM of consecutive integers is their product.
Let the number be 'n' & 'n+1' ; consecutive. Hence n(n+1) = 7310 ( product) n^(2) + n = 7310 Complete the Square ( n + 1/2)^(2) - (1/2)^(2) = 7310 ( n + 1/2)^2 - 1/4 = 7310 (n + 1/2)^(2) = 7310.25 Square root both sides n+ 1/2 = +/- 85.5 (NB 1/2 = 0.5) n = 85.5 - 0.5 = 85 Hence n + 1 = 86 Verification 85 X 86 = 7310
The numbers are -6, -5, -4 and -3.