Let's represent the four consecutive integers as x, x+1, x+2, and x+3. The sum of these integers can be expressed as x + (x+1) + (x+2) + (x+3) = 4x + 6. We are given that this sum is equal to 182, so we can set up the equation 4x + 6 = 182. Solving for x, we find x = 44. Therefore, the four consecutive integers are 44, 45, 46, and 47.
Let's denote the first integer as x. The sum of 4 consecutive integers starting from x can be expressed as x + (x+1) + (x+2) + (x+3) = 182. Simplifying this equation gives 4x + 6 = 182. Solving for x, we find that the first integer is 44.
There are four consecutive odd integers: 81, 83, 85 and 87.
The integers are 3, 4, 5 and 6.
There is no pair of consecutive even integers whose sum is 264 - as their average is divisible by 4, that must mean that the sum of the unit digits of each of the pair of numbers could never be a multiple of 4 - which 264 is.
20, 21, 22 and 23.
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
-4 and -5
If n is the smallest of the four integers, their sum is 4n+6.
Let's denote the first integer as x. The sum of 4 consecutive integers starting from x can be expressed as x + (x+1) + (x+2) + (x+3) = 182. Simplifying this equation gives 4x + 6 = 182. Solving for x, we find that the first integer is 44.
There are four consecutive odd integers: 81, 83, 85 and 87.
4 and 5
-3,-4,-5
The greatest integer is 24.
118
The integers are -2, 0, 2 and 4.
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
The sum of any two consecutive integers is odd. Try it out. 3 + 4 = 7 4 + 5 = 9 If it works for those, it works for all of them.