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Let's represent the four consecutive integers as x, x+1, x+2, and x+3. The sum of these integers can be expressed as x + (x+1) + (x+2) + (x+3) = 4x + 6. We are given that this sum is equal to 182, so we can set up the equation 4x + 6 = 182. Solving for x, we find x = 44. Therefore, the four consecutive integers are 44, 45, 46, and 47.
182/4 = 45.5
so of the four numbers 45 will be the second
44 + 45 + 46 + 47 = 89 + 93 = 182
fewfw
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The sum of 4 consecutive integers is 182 What is the first integer?
Oh, isn't that a happy little math problem! To find the first integer, you can use a simple formula. Since the sum of 4 consecutive integers is 182, you can divide 182 by 4 to find the average value of the integers. Then, you can work backwards to find the first integer. Just remember, there are no mistakes in math, only happy little accidents!
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There is no pair of consecutive even integers whose sum is 264 - as their average is divisible by 4, that must mean that the sum of the unit digits of each of the pair of numbers could never be a multiple of 4 - which 264 is.
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If n is the smallest of the four integers, their sum is 4n+6.
The sum of 4 consecutive integers is 182 What is the first integer?
Oh, isn't that a happy little math problem! To find the first integer, you can use a simple formula. Since the sum of 4 consecutive integers is 182, you can divide 182 by 4 to find the average value of the integers. Then, you can work backwards to find the first integer. Just remember, there are no mistakes in math, only happy little accidents!
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The sum of any two consecutive integers is odd. Try it out. 3 + 4 = 7 4 + 5 = 9 If it works for those, it works for all of them.
