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Let's represent the four consecutive integers as x, x+1, x+2, and x+3. The sum of these integers can be expressed as x + (x+1) + (x+2) + (x+3) = 4x + 6. We are given that this sum is equal to 182, so we can set up the equation 4x + 6 = 182. Solving for x, we find x = 44. Therefore, the four consecutive integers are 44, 45, 46, and 47.

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More answers

182/4 = 45.5

so of the four numbers 45 will be the second

44 + 45 + 46 + 47 = 89 + 93 = 182

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Wiki User

7y ago
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Q: What are 4 consecutive integers of the sum of 182?
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