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Let's represent the four consecutive integers as x, x+1, x+2, and x+3. The sum of these integers can be expressed as x + (x+1) + (x+2) + (x+3) = 4x + 6. We are given that this sum is equal to 182, so we can set up the equation 4x + 6 = 182. Solving for x, we find x = 44. Therefore, the four consecutive integers are 44, 45, 46, and 47.
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4 consecutive integers whose sum is 336?
There are four consecutive odd integers: 81, 83, 85 and 87.
The sum of 4 consecutive integers is 182 What is the first integer?
Oh, isn't that a happy little math problem! To find the first integer, you can use a simple formula. Since the sum of 4 consecutive integers is 182, you can divide 182 by 4 to find the average value of the integers. Then, you can work backwards to find the first integer. Just remember, there are no mistakes in math, only happy little accidents!
The sum of four consecutive inters is 18 find the integers?
The integers are 3, 4, 5 and 6.
What are the consecutive even integers of whose sum is 264?
There is no pair of consecutive even integers whose sum is 264 - as their average is divisible by 4, that must mean that the sum of the unit digits of each of the pair of numbers could never be a multiple of 4 - which 264 is.
What are 4 consecutive integers whose sum is 86?
20, 21, 22 and 23.
