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Let x=1st integer
x+1=2nd integer
x+2=3rd integer
5(x+x+1+x+2)=150
5(3x+3)=150
15x+15=150
15x=135
x=9
So you put what x is
1st integer (x)= 9
Since it's three consecutive integers, you add one to the 2nd integer
2nd integer (x+1)= 10
Then you do the same thing for the third integer
3rd integer (x+2)= 11
What else can I help you with?
What are the Five consecutive odd integers starting with negative three?
-3, -1, 1, 3, 5
If the sum of the first two of the five consecutive odd integers is 52 what is the sum of the last two integers?
(2x - 1) + (2x + 1) = 524x = 52x = 13The first 2 of 5 consecutive odd integers are 25 and 27.(Check: 25 + 27 = 52 yay!)The last 2 of 5 are 31 and 33.Their sum is 64.
Translate this phrase into an algebraic equation Eight less than five times a number is seven more than the number?
Let's represent the number as (x). The phrase "Eight less than five times a number" can be translated to (5x - 8), and "is seven more than the number" can be translated to (x + 7). Therefore, the algebraic equation representing the given phrase is (5x - 8 = x + 7).
Five consecutive odd integers starting with -3?
There are two ways to approach this. You could use odd integers larger or smaller than -3. If you go larger than -3, the answer is: -3, -1, 1, 3, 5. If you go smaller than -3, the answer is: -3, -5, -7, -9, -11.
If the sum of the first two of the five consecutive odd integers is 52what is the sum of the last two integers?
Let the first odd integer be x, then the second one is x + 2. So we have: x + (x + 2) = 52 2x + 2 = 52 subtract 2 to both sides 2x = 50 divide by 2 to both sides x = 25 Thus, the first number is 25. Since consecutive odd integers grow by 2, then the second is 27, the third is 29, the fourth is 31, and the fifth integer is 33. So the sum of the last two integers is 64 ( 31 + 33).
Five times the smallest of three consecutive even integers is 10 more than twice the largest. find the integers?
5872345098234783904672083946728390752430689723409687298290843 theres your answer
Five times the first of three consecutive even integers is 14 more then 3 times the second?
Three consecutive even integers can be represented by a-2, a & a+2.Five times the first is 5a-10. Three times the second is 3a.5a-10 is 14 more than 3a, so 5a-10 = 3a+14Adding 10 to both sides: 5a = 3a+24Taking 3a from both sides: 2a = 24Therefore a=12The three consecutive even integers are 22, 24 and 26.
What are three consecutive integers such that the sum of five times the first six times the second and seven times the third is 148?
This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.
When the smaller of two consecutive integers is added to five times the larger the result is 65?
The integers are 10 and 11.
What are the Five consecutive odd integers starting with negative three?
-3, -1, 1, 3, 5
What is the sum of four consecutive even integers is 2 more than five times the first integer?
The integers would begin with 10.
What are The product of two consecutive positive integers is 27 more than five times the larger integer. Find the integers?
One possible answer is -4 and -3.
Find two consecutive odd integers such that five less than three times the second equals four times the first. HELP?
Integers are a and a + 2.3 x (a + 2) - 5 = 4a3a + 6 - 5 = 4aa = 1Integers are 1 and 3 (9 - 5 = 4)
What is a set of five consecutive integers that are all composite?
4,6,8,9,10
Find 3 consecutive even integers if the product of the first integer and two two less than the second integer is four more than five times the third integer and what is the let statement?
The let statement is: let the smallest of the three integers be x.
The sum of three consecutive odd integers is the same as five times the greatest of these integers find the smallest and the largest of these integers?
x + (x + 2) + (x + 4) = 5 (x + 4) so 3x + 6 = 5x + 20 ie -2x = 14 so x = -7 and integers are -7, -5 and -3 Sneaky!
What is the greatest of 5 consecutive integers if the sum of these integers equals -45?
50
