Best Answer

Let x=1st integer

x+1=2nd integer

x+2=3rd integer

5(x+x+1+x+2)=150

5(3x+3)=150

15x+15=150

15x=135

x=9

So you put what x is

1st integer (x)= 9

Since it's three consecutive integers, you add one to the 2nd integer

2nd integer (x+1)= 10

Then you do the same thing for the third integer

3rd integer (x+2)= 11

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Q: Five times the sum of three consecutive integers is 150 what are the integers?

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-3, -1, 1, 3, 5

Translate this phrase into an algebraic equation The product of two consecutive multiple of three integers?

(2x - 1) + (2x + 1) = 524x = 52x = 13The first 2 of 5 consecutive odd integers are 25 and 27.(Check: 25 + 27 = 52 yay!)The last 2 of 5 are 31 and 33.Their sum is 64.

There are two ways to approach this. You could use odd integers larger or smaller than -3. If you go larger than -3, the answer is: -3, -1, 1, 3, 5. If you go smaller than -3, the answer is: -3, -5, -7, -9, -11.

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Three consecutive even integers can be represented by a-2, a & a+2.Five times the first is 5a-10. Three times the second is 3a.5a-10 is 14 more than 3a, so 5a-10 = 3a+14Adding 10 to both sides: 5a = 3a+24Taking 3a from both sides: 2a = 24Therefore a=12The three consecutive even integers are 22, 24 and 26.

This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.

The integers are 10 and 11.

The integers would begin with 10.

-3, -1, 1, 3, 5

One possible answer is -4 and -3.

4,6,8,9,10

Integers are a and a + 2.3 x (a + 2) - 5 = 4a3a + 6 - 5 = 4aa = 1Integers are 1 and 3 (9 - 5 = 4)

The integers are -4, -3, -2, -1, 0, 1, 2, 3, 4 and 5. The largest is five.

The let statement is: let the smallest of the three integers be x.

x + (x + 2) + (x + 4) = 5 (x + 4) so 3x + 6 = 5x + 20 ie -2x = 14 so x = -7 and integers are -7, -5 and -3 Sneaky!

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