Wiki User
∙ 2011-02-03 02:20:16Let x=1st integer
x+1=2nd integer
x+2=3rd integer
5(x+x+1+x+2)=150
5(3x+3)=150
15x+15=150
15x=135
x=9
So you put what x is
1st integer (x)= 9
Since it's three consecutive integers, you add one to the 2nd integer
2nd integer (x+1)= 10
Then you do the same thing for the third integer
3rd integer (x+2)= 11
Wiki User
∙ 2011-02-03 02:20:16-3, -1, 1, 3, 5
Translate this phrase into an algebraic equation The product of two consecutive multiple of three integers?
(2x - 1) + (2x + 1) = 524x = 52x = 13The first 2 of 5 consecutive odd integers are 25 and 27.(Check: 25 + 27 = 52 yay!)The last 2 of 5 are 31 and 33.Their sum is 64.
There are two ways to approach this. You could use odd integers larger or smaller than -3. If you go larger than -3, the answer is: -3, -1, 1, 3, 5. If you go smaller than -3, the answer is: -3, -5, -7, -9, -11.
google it or bing it
5872345098234783904672083946728390752430689723409687298290843 theres your answer
Three consecutive even integers can be represented by a-2, a & a+2.Five times the first is 5a-10. Three times the second is 3a.5a-10 is 14 more than 3a, so 5a-10 = 3a+14Adding 10 to both sides: 5a = 3a+24Taking 3a from both sides: 2a = 24Therefore a=12The three consecutive even integers are 22, 24 and 26.
This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.
The integers are 10 and 11.
The integers would begin with 10.
-3, -1, 1, 3, 5
One possible answer is -4 and -3.
4,6,8,9,10
Integers are a and a + 2.3 x (a + 2) - 5 = 4a3a + 6 - 5 = 4aa = 1Integers are 1 and 3 (9 - 5 = 4)
The integers are -4, -3, -2, -1, 0, 1, 2, 3, 4 and 5. The largest is five.
The let statement is: let the smallest of the three integers be x.
x + (x + 2) + (x + 4) = 5 (x + 4) so 3x + 6 = 5x + 20 ie -2x = 14 so x = -7 and integers are -7, -5 and -3 Sneaky!