Best Answer

Let x=1st integer

x+1=2nd integer

x+2=3rd integer

5(x+x+1+x+2)=150

5(3x+3)=150

15x+15=150

15x=135

x=9

So you put what x is

1st integer (x)= 9

Since it's three consecutive integers, you add one to the 2nd integer

2nd integer (x+1)= 10

Then you do the same thing for the third integer

3rd integer (x+2)= 11

Q: Five times the sum of three consecutive integers is 150 what are the integers?

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-3, -1, 1, 3, 5

Translate this phrase into an algebraic equation The product of two consecutive multiple of three integers?

(2x - 1) + (2x + 1) = 524x = 52x = 13The first 2 of 5 consecutive odd integers are 25 and 27.(Check: 25 + 27 = 52 yay!)The last 2 of 5 are 31 and 33.Their sum is 64.

There are two ways to approach this. You could use odd integers larger or smaller than -3. If you go larger than -3, the answer is: -3, -1, 1, 3, 5. If you go smaller than -3, the answer is: -3, -5, -7, -9, -11.

Let the first odd integer be x, then the second one is x + 2. So we have: x + (x + 2) = 52 2x + 2 = 52 subtract 2 to both sides 2x = 50 divide by 2 to both sides x = 25 Thus, the first number is 25. Since consecutive odd integers grow by 2, then the second is 27, the third is 29, the fourth is 31, and the fifth integer is 33. So the sum of the last two integers is 64 ( 31 + 33).

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Three consecutive even integers can be represented by a-2, a & a+2.Five times the first is 5a-10. Three times the second is 3a.5a-10 is 14 more than 3a, so 5a-10 = 3a+14Adding 10 to both sides: 5a = 3a+24Taking 3a from both sides: 2a = 24Therefore a=12The three consecutive even integers are 22, 24 and 26.

This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.

The integers are 10 and 11.

The integers would begin with 10.

-3, -1, 1, 3, 5

One possible answer is -4 and -3.

Integers are a and a + 2.3 x (a + 2) - 5 = 4a3a + 6 - 5 = 4aa = 1Integers are 1 and 3 (9 - 5 = 4)

4,6,8,9,10

The let statement is: let the smallest of the three integers be x.

x + (x + 2) + (x + 4) = 5 (x + 4) so 3x + 6 = 5x + 20 ie -2x = 14 so x = -7 and integers are -7, -5 and -3 Sneaky!

Translate this phrase into an algebraic equation The product of two consecutive multiple of three integers?