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Let x=1st integer

x+1=2nd integer

x+2=3rd integer

5(x+x+1+x+2)=150

5(3x+3)=150

15x+15=150

15x=135

x=9

So you put what x is

1st integer (x)= 9

Since it's three consecutive integers, you add one to the 2nd integer

2nd integer (x+1)= 10

Then you do the same thing for the third integer

3rd integer (x+2)= 11

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โˆ™ 2011-02-03 02:20:16
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Q: Five times the sum of three consecutive integers is 150 what are the integers?
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