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What 12 x 0 1?

Updated: 4/28/2022
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what 12 x 0 + 1 =

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Q: What 12 x 0 1?
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What are the values of X in the equation 2x2 equals 10x plus 12?

2x2 = 10x + 12 2x2 - 10x - 12 = 0 x2 -5x -6 = 0 x2 - 6x + x - 6 = 0 x(x -6) + 1(x -6) = 0 (x+1)(x-6) = 0 x = -1 or x = 6


How to solve X cubed plus X squared=12?

To solve the equation X^3 + X^2 = 12, you'll need to find the values of X that satisfy the equation. Here's how you can solve it: Rewrite the equation in standard form, setting it equal to zero: X^3 + X^2 - 12 = 0 This equation is a cubic equation. To solve it, you can try factoring it or use numerical methods such as the Newton-Raphson method. In this case, factoring is a suitable method. First, look for common factors that can be factored out from all the terms. In this case, you can factor out X^2: X^2(X + 1) - 12 = 0 Now, you have a quadratic equation in the form (X^2 - 12)(X + 1) = 0. This equation can be factored further: (X - √12)(X + √12)(X + 1) = 0 You now have three factors: a) X - √12 = 0 b) X + √12 = 0 c) X + 1 = 0 Solve each of these equations for X: a) X - √12 = 0 X = √12 b) X + √12 = 0 X = -√12 c) X + 1 = 0 X = -1 So, the solutions for X in the equation X^3 + X^2 = 12 are X = √12, X = -√12, and X = -1.


5x squared plus 7x equals 12?

5x2+7x = 12 5x2+7x-12 = 0 (5x+12)(x-1) = 0 x = -12/5 or x = 1


How do you write 712000 in expanded form?

712,000 = (7 x 1000000) + (1 x 100000) + (2 x 10000) + (0 x 1000) + (0 x 100) + (0 x 10) + (0 x 1)


What are th ltiples of twelve?

If you mean "multiples", just calculate: 12 x 0 12 x 1 12 x 2 etc. Also, if you want: 12 x (-1) 12 x (-2) etc.


How do you solve x squared plus 12x?

Factor. X^2 + 12X X(X + 12) = 0 X = 0 ------------- X + 12 = 0 X = - 12 --------------


What two numbers multiply to get -12 and add to get -11?

-23


What is 12 thousandths in expanded form?

12 thousandths (0.012) = (0 x 1) . (0/10) + (1/100) + (2/1000)


X2 - x - 12 equals 0?

x²-x-12=0 x1=-(-1/2) - Square root of ((-1/2)²+12) x1=0.5 - 3.5 x1=-3 x2=-(-1/2) + Square root of ((-1/2)²+12) x2=0.5 + 3.5 x2=4


Solve for x in x plus 1 over x equals -7 over x - 12?

You have : -------------- ( x + 1 ) / ( x ) = ( -7 ) / ( x - 12 ) Multiply both sides by ( x ) ( x - 12 ) and get : ( x + 1 ) ( x - 12 ) = ( -7 ) ( x ) x^2 - 12x + x - 12 = -7x x^2 - 4x - 12 = 0 Factor the above : ( x - 6 ) ( x + 2 ) = 0 There are two roots : x = 6 <------------------ x = -2 <---------------


12 with an exponent of 0?

120= 1 Anything with exponent 0 is 1, because if you multiply n0 by n0 you add the indices to get n0 and anything nonzero that when multiplied by itself gives itself, must be 1: if x2 = x then x2 - x = 0, so x(x-1)=0, so x=1 or 0.


What is x squared plus 13x plus 12?

It's a quadratic expression: x²+13x+12 If, for example, x²+13x+12 = 0 then there are 2 roots, x=-1 and x=-12