To calculate the total number of possible 4-digit codes using the numbers 1, 2, and 3, we can use the fundamental principle of counting. Since we have 3 choices for each digit and we are choosing 4 digits, the total number of possible codes is 3 x 3 x 3 x 3 = 81. Therefore, there are 81 possible 4-digit codes that can be formed using the numbers 1, 2, and 3.
There are 210 4 digit combinations and 5040 different 4 digit codes.
Any 4 from 10 in any order = 10 x 9 x 8 x 7 = 5040
There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.
10,000
There are 256. Some of them are: 1111, 1112, 1113, 1114, 1121, ... 2111, 2112, 2113, ... 3111, 3112, ... 4111, etc.
There are 210 4 digit combinations and 5040 different 4 digit codes.
There are 10000 such codes. Each of the numbers 0-9 can be in the first position. With each such first digit, each of the numbers 0-9 can be in the second position. With each such pair of the first two digits, each of the numbers 0-9 can be in the third position. etc.
Any 4 from 10 in any order = 10 x 9 x 8 x 7 = 5040
1,000 of them. The list of possibilities will look exactly like the counting numbers from 000 to 999 .
1000
There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.
Total number of possible 3-digit numbers = 9!x10!10!
The possible 4 digit codes using the numbers 0-9 are every number between 0 and 9999. For numbers that have less than 4 digits, just precede the number with 0's. 10,000 possibilities
10,000
103 = 1000 in all.
9999999999 100000000
Using the digits of 1345678, there are 210 three digit numbers in which no digit is repeated.