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To calculate the total number of possible 4-digit codes using the numbers 1, 2, and 3, we can use the fundamental principle of counting. Since we have 3 choices for each digit and we are choosing 4 digits, the total number of possible codes is 3 x 3 x 3 x 3 = 81. Therefore, there are 81 possible 4-digit codes that can be formed using the numbers 1, 2, and 3.

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ProfBot

1mo ago
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Wiki User

11y ago

Since you've only given us 3 digits to put in 4 places, we have to assume

that it's OK to use the same digit more than once in a code. So we're also

going to assume that there's no limit on repetition.

The first digit can be any one of 3. For each one . . .

The second digit can be any one of 3. For each one . . .

The third digit can be any one of 3. For each one . . .

The fourth digit can be any one of 3.

Total possibilities = 3 x 3 x 3 x 3 = 81 possible codes.

Which are:

1111, 1112, 1113, 1121, 1122, 1123, 1131, 1132, 1133, 1211, 1212, 1213, 1221, 1222, 1223, 1231, 1232, 1233, 1311, 1312, 1313, 1321, 1322, 1323, 1331, 1332, 1333, 2111, 2112, 2113, 2121, 2122, 2123, 2131, 2132, 2133, 2211, 2212, 2213, 2221, 2222, 2223, 2231, 2232, 2233, 2311, 2312, 2313, 2321, 2322, 2323, 2331, 2332, 2333, 3111, 3112, 3113, 3121, 3122, 3123, 3131, 3132, 3133, 3211, 3212, 3213, 3221, 3222, 3223, 3231, 3232, 3233, 3311, 3312, 3313, 3321, 3322, 3323, 3331, 3332, 3333

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SHANNON MONROE

Lvl 2
1y ago

1111, 1112, 1113, 1121, 1122, 1123, 1131, 1132, 1133, 1211, 1212, 1213, 1221, 1222, 1223, 1231, 1232, 1233, 1311, 1312, 1313, 1321, 1322, 1323, 1331, 1332, 1333, 2111, 2112, 2113, 2121, 2122, 2123, 2131, 2132, 2133, 2211, 2212, 2213, 2221, 2222, 2223, 2231, 2232, 2233, 2311, 2312, 2313, 2321, 2322, 2323, 2331, 2332, 2333, 3111, 3112, 3113, 3121, 3122, 3123, 3131, 3132, 3133, 3211, 3212, 3213, 3221, 3222, 3223, 3231, 3232, 3233, 3311, 3312, 3313, 3321, 3322, 3323, 3331, 3332, 3333

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Q: What are all the possible 4 digit codes using the numbers 123?
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