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To calculate the total number of possible 4-digit codes using the numbers 1, 2, and 3, we can use the fundamental principle of counting. Since we have 3 choices for each digit and we are choosing 4 digits, the total number of possible codes is 3 x 3 x 3 x 3 = 81. Therefore, there are 81 possible 4-digit codes that can be formed using the numbers 1, 2, and 3.
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JordanSince you've only given us 3 digits to put in 4 places, we have to assume
that it's OK to use the same digit more than once in a code. So we're also
going to assume that there's no limit on repetition.
The first digit can be any one of 3. For each one . . .
The second digit can be any one of 3. For each one . . .
The third digit can be any one of 3. For each one . . .
The fourth digit can be any one of 3.
Total possibilities = 3 x 3 x 3 x 3 = 81 possible codes.
Which are:
1111, 1112, 1113, 1121, 1122, 1123, 1131, 1132, 1133, 1211, 1212, 1213, 1221, 1222, 1223, 1231, 1232, 1233, 1311, 1312, 1313, 1321, 1322, 1323, 1331, 1332, 1333, 2111, 2112, 2113, 2121, 2122, 2123, 2131, 2132, 2133, 2211, 2212, 2213, 2221, 2222, 2223, 2231, 2232, 2233, 2311, 2312, 2313, 2321, 2322, 2323, 2331, 2332, 2333, 3111, 3112, 3113, 3121, 3122, 3123, 3131, 3132, 3133, 3211, 3212, 3213, 3221, 3222, 3223, 3231, 3232, 3233, 3311, 3312, 3313, 3321, 3322, 3323, 3331, 3332, 3333
1111, 1112, 1113, 1121, 1122, 1123, 1131, 1132, 1133, 1211, 1212, 1213, 1221, 1222, 1223, 1231, 1232, 1233, 1311, 1312, 1313, 1321, 1322, 1323, 1331, 1332, 1333, 2111, 2112, 2113, 2121, 2122, 2123, 2131, 2132, 2133, 2211, 2212, 2213, 2221, 2222, 2223, 2231, 2232, 2233, 2311, 2312, 2313, 2321, 2322, 2323, 2331, 2332, 2333, 3111, 3112, 3113, 3121, 3122, 3123, 3131, 3132, 3133, 3211, 3212, 3213, 3221, 3222, 3223, 3231, 3232, 3233, 3311, 3312, 3313, 3321, 3322, 3323, 3331, 3332, 3333
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How many possible 4 digit combinations are there using 0-9. how many different combination codes are possible?
There are 210 4 digit combinations and 5040 different 4 digit codes.
What are all the possible 4 digit codes using the numbers 0 to 9 without using the same digit twice in each code?
Any 4 from 10 in any order = 10 x 9 x 8 x 7 = 5040
How many possible 3 digit numbers can be made using the digits 604?
There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.
How many 3-digit codes using digits 0 through 9 are possible if repetitions are allowed?
10,000
What are all the possible 4 digit codes using the numbers 1-4?
There are 256. Some of them are: 1111, 1112, 1113, 1114, 1121, ... 2111, 2112, 2113, ... 3111, 3112, ... 4111, etc.
