(x - 4) or (x + 8)
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
You can work this out with long division, by checking to see if (x2 - 1) is a factor of (2x4 + 4x3 - x2 + 4x - 3). It is. Unfortunately, the WikiAnswers system is somewhat limited in depicting things such as long division, so we won't be able to represent it here. In short though, (2x4 + 4x3 - x2 + 4x - 3) / (x2 + 1) is equal to 2x2 + 4x - 3. which means that: (x2 + 1) / (2x4 + 4x3 - x2 + 4x - 3) = (x2 + 1) / (x2 + 1)(2x2 + 4x - 3) = 1 / (2x2 + 4x - 3)
y = 4x-3
x - 4 APEX
(x - 4) or (x + 8)
x2 + 4x - 96 = (x - 8)(x + 12).
(x + 12)(x + 7)
x2+4x-12 = (x-2)(x+6) when factored
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
(x + 12)(x - 8)
(6 - x)(2 + x)
x2 + 4x - 9 = 5x + 3 ∴ x2 - x - 12 = 0 ∴ (x + 3)(x - 4) = 0 ∴ x ∈ {-3, 4}
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
x2 + 4x + 3 = (x + 1)(x + 3)
No. x2 -4x - 12 = (x + 2)(x - 6)
x2+14x+40 = (x+4)(x+10) when factored