5
well the first four terms are n=1,2,3 and 4 so just substitute those numbers into k=3n so k= 3,6,9,12
2
6
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
5
24,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100.
well the first four terms are n=1,2,3 and 4 so just substitute those numbers into k=3n so k= 3,6,9,12
The first four terms are 3 9 27 81 and 729 is the 6th term.
2
6
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
im a biginner
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
9, 10, 11 and 12
George Washington
No. Roosevelt was the first and only US President to serve four terms.