14
5
well the first four terms are n=1,2,3 and 4 so just substitute those numbers into k=3n so k= 3,6,9,12
2
6
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
5
24,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100.
well the first four terms are n=1,2,3 and 4 so just substitute those numbers into k=3n so k= 3,6,9,12
The first four terms are 3 9 27 81 and 729 is the 6th term.
2
The first step in factoring a polynomial with four terms is to look for a common factor in pairs of terms. This process is often called grouping. You can group the first two terms together and the last two terms together, factor out the common factors from each pair, and then check if a common binomial factor emerges that can be factored out further.
6
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
im a biginner
The first step in factoring a polynomial with four terms is to look for a common factor among the terms. If no common factor exists, you can try grouping the terms into two pairs and factor each pair separately. This often reveals a common binomial factor that can be factored out, simplifying the polynomial further.
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
9, 10, 11 and 12