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The expression 12-2n represents a sequence of numbers where each term is obtained by subtracting twice the position number from 12. The first term (n=1) is calculated as 12-2(1) = 10. The second term (n=2) is 12-2(2) = 8. The third term (n=3) is 12-2(3) = 6. The fourth term (n=4) is 12-2(4) = 4.
Oh, what a happy little question! So, if we start with 12 and subtract 2 times n, the first four terms would be: 12-2(1), 12-2(2), 12-2(3), and 12-2(4). Remember, there are no mistakes, just happy little accidents in math!
Sure thing, honey. The first four terms for 12-2n are 12, -2n, -2n, -2n. Just slap that -2n on repeat like a bad playlist. Happy math-ing!
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well the first four terms are n=1,2,3 and 4 so just substitute those numbers into k=3n so k= 3,6,9,12
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Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24