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Using the quadratic formula or completing the square would be the way to solve this one.
x=(-b+sqr(b^2-4ac))/2a; (-b-sqrb^2-4ac))/2a
a=2
b=-3
c=-4
x=(3+sqr(9+32))/4
x=(3+sqr41)/4
Once you decide to what accuracy you want to get the square root of 41 then you can get the decimal equivalents. A little more than negative 1 and a little more than positive two.
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What is the nature of the roots of the equation 2xsquared-6x plus 2 equals 0?
It has roots x = 2.618 and x = 0.38197
What are the roots of the quadratic equation x2 plus 14x plus 45 equals 0?
The roots are: x = -5 and x = -9
How do you find the sum of the roots of the equation x2 plus 5x plus 9 equals 0?
This quadratic equation has no real roots because its discriminant is less than zero.
Which equation has imaginary roots a.x2-1 equals 0 b.x2-2 equals 0 c.x2 plus x plus 1 equals 0 d.x2-x-1 equals 0?
To find which has imaginary roots, use the discriminant of the quadratic formula (b2 - 4ac) and see if it's less than 0. (The quadratic formula corresponds to general form of a quadratic equation, y = ax2 + bx + c)A) x2 - 1 = 0= 0 - 4(1)(-1) = 4Therefore, the roots are not imaginary.B) x2 - 2 = 0= 0 - 4(1)(-2) = 8Therefore, the roots are not imaginary.C) x2 + x + 1 = 0= 1 - 4(1)(1) = -3Therefore, the roots are imaginary.D) x2 - x - 1 = 0= 1 - 4(1)(-1) = 5Therefore, the roots are not imaginary.The equation x2 + x + 1 = 0 has imaginary roots.
Roots of the equation x 2 plus 5x plus 7 equals 0 will be?
There are no real root. The complex roots are: [-5 +/- sqrt(-3)] / 2
What is the number and type of roots of the equation x2-4x-32 equals 0?
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
What roots of the quadratic equation are equivalent to xx-x-12 equals 0?
-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
In the quadratic equation ax2 plus bx plus c 0 if b2 - 4ac?
If you mean b^2 -4ac then it is the discriminant of a quadratic equation. If the discriminant equals 0 then the equation has 2 equal roots. If the discriminant is greater than 0 then the equation has 2 different roots. If the discriminant is less than 0 then it has no real roots.
What is the nature of the roots of the equation 2xsquared-6x plus 2 equals 0?
It has roots x = 2.618 and x = 0.38197
What is the roots of the equation 2xsquare-3x-4 equals 0?
2x2 -3x - 4 = 0 use the qudratic equation and your answers are 1.137458609 and -2.637458609
What is the product of the roots of the equation 2xsquare-x-2 equals 0?
The product of the roots of the equation 2x2 -x -2 = 2 is 2x2 -x -2 = 2.
What are the roots of the quadratic equation x2 plus 14x plus 45 equals 0?
The roots are: x = -5 and x = -9
What is the answer to the equation 2x2 - 10x plus 7 equals 0?
The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842
How do you find the sum of the roots of the equation x2 plus 5x plus 9 equals 0?
This quadratic equation has no real roots because its discriminant is less than zero.
Which equation has imaginary roots a.x2-1 equals 0 b.x2-2 equals 0 c.x2 plus x plus 1 equals 0 d.x2-x-1 equals 0?
To find which has imaginary roots, use the discriminant of the quadratic formula (b2 - 4ac) and see if it's less than 0. (The quadratic formula corresponds to general form of a quadratic equation, y = ax2 + bx + c)A) x2 - 1 = 0= 0 - 4(1)(-1) = 4Therefore, the roots are not imaginary.B) x2 - 2 = 0= 0 - 4(1)(-2) = 8Therefore, the roots are not imaginary.C) x2 + x + 1 = 0= 1 - 4(1)(1) = -3Therefore, the roots are imaginary.D) x2 - x - 1 = 0= 1 - 4(1)(-1) = 5Therefore, the roots are not imaginary.The equation x2 + x + 1 = 0 has imaginary roots.
What are the roots of the quadratic equation x2 - 6x plus 8 equals 0?
x = 2 and x = 4
Roots of the equation x 2 plus 5x plus 7 equals 0 will be?
There are no real root. The complex roots are: [-5 +/- sqrt(-3)] / 2
