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Using the quadratic formula or completing the square would be the way to solve this one.
x=(-b+sqr(b^2-4ac))/2a; (-b-sqrb^2-4ac))/2a
a=2
b=-3
c=-4
x=(3+sqr(9+32))/4
x=(3+sqr41)/4
Once you decide to what accuracy you want to get the square root of 41 then you can get the decimal equivalents. A little more than negative 1 and a little more than positive two.
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