Id x2 = 169, then x = ±√169 = {-13, +13}
x2 + 49 = 0
-167
An equation would be....,X2 - 10X + 16 = 0easy factoring(X - 2)(X - 8)==========So.X = 2====
The quadratic formula can be used to find the solutions of a quadratic equation - not a linear or cubic, or non-polynomial equation. The quadratic formula will always provide the solutions to a quadratic equation - whether the solutions are rational, real or complex numbers.
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
x2 + 49 = 0
-167
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
y2 = 169 Square root both sides: y = 13
If: x2 = 3 Then: x = square root of 3
x2 - 12x + 35
13
x2 = 81 Square root both sides:- x = +/- 9
x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
38
An equation would be....,X2 - 10X + 16 = 0easy factoring(X - 2)(X - 8)==========So.X = 2====
Use the quadratic equation formula to find the solutions to this equation.