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What are the values of k when kx plus y equals 4 is tangent to the curve y equals x squared plus 8 showing work?
Wiki User
∙ 8y ago
If: kx+y = 4 and y = x^2+8
Then: x^2+8 = 4-kx => x^2+4+kx = 0
For the line to be tangent to the curve the discriminant of b^2-4(ac) must = 0
So: k^2-4(1*4) = 0 => k^2 -16 = 0 => k^2 = 16 => k = +/- 4
Therefore: y+4x = 4 and y-4x = 4 are tangents to the curve y = x^2+8
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∙ 8y ago
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