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Domain and range of y equals 2sinx?
The domain is the set of all possible x values, for this problem it would be negative infinity to positive infinity. The range is the set of all possible y values, for this problem it would be -2 too +2
What 1 and 4 out of 5 equal to?
It is equal to 1.8It is equal to 1.8It is equal to 1.8It is equal to 1.8
Why isn't a parallelogram a regular polygon?
Angles are not necessarily equal, and sides are not necessarily equal in length.Angles are not necessarily equal, and sides are not necessarily equal in length.Angles are not necessarily equal, and sides are not necessarily equal in length.Angles are not necessarily equal, and sides are not necessarily equal in length.
Is 5.20 greater than 5.2?
It is the same. So they are equal
What is equal to 428?
428 is equal to 428. No other number is equal to 428.
What is a numerical value for x if cos2x plus 2sinx-2 equals 0?
cos2x + 2sinx - 2 = 0 (1-2sin2x)+2sinx-2=0 -(2sin2x-2sinx+1)=0 -2sinx(sinx+1)=0 -2sinx=0 , sinx+1=0 sinx=0 , sinx=1 x= 0(pi) , pi/2 , pi
How do you solve 2Sinx 1 equals 0?
2sinx+1 equals 0
What is the period of y equals 2sinx?
The same as the period of y = sin x. This period is equal to (2 x pi).
Solve 2sinx-sin3x equals 0?
2sinx - sin3x = 0 2sinx - 3sinx + 4sin3x = 0 4sin3x - sinx = 0 sinx(4sin2x - 1) = 0 sinx*(2sinx - 1)(2sinx + 1) = 0 so sinx = 0 or sinx = -1/2 or sinx = 1/2 It is not possible to go any further since the domain for x is not defined.
What is the derivative of 2 cos x -2 sin x?
4
What is the limit of 2sinx divided by4 as x goes to pi?
0.5
How do you solve 4 sin squared x equals 1?
4 sin2x = 1. Then, (2sinx)2 = 1, 2sinx = ±1, and sinx = ±½. Whence, x = 90° or 270°; or, in radians, x = π/2 or 3π/2.
How should I solve 3sin2x 2sinx 1?
3*sin2x = 2*sinx +1
What is the anti-derivative of -2cosx?
take out the constant -2 then take the intergral of cosx this will give you sinx your answer is -2sinx
How do you convert r equals 2sinX into rectangular form?
You also need an equation for y in order to convert to rectangular form.
How do you solve the equation cos squared x minus 2sinx?
The information you provided in your question does not include an =. Therefore it is not an equation; it is an expression
Derivative of 1 plus cos2x?
First find the derivative of each term. The derivative of any constant is zero, so d(1)/dx=0. To find the derivative of cos2x, use the chain rule. d(cos2x)/dx=-sin(2x)(2)=-2sin(2x) So the answer is 0-2sinx, or simply -2sinx
