It is difficult to tell because this site uses a useless browser: one which cannot accept most mathematical symbols. So all we can see of the given equation is "y x2 10x plus 30", and the options appear as "y (x 5)2 plus 55 y (x 5)2 plus 30 y (x 5)2 5 y (x 5)2 plus 5".
If the equation is y = x^2 - 10x + 30 then the answer is y = (x - 5) ^2 + 5.
Y = X2 + 6X + 2set to 0X2 + 6X + 2 = 0X2 + 6X = - 2now, halve the linear coefficient ( 6 ), square it and add it to both sidesX2 + 6X + 9 = - 2 + 9gather terms on the right and factor the left(X + 3)2 = 7(X + 3)2 - 7 = 0==============vertex form(- 3, - 7)=======vertex
It is not an equation, but q2 meaning q^2 represents q being multiplied by itself.
It represents an algebraic equation in the variable, k.
y = x + 2 - 4 is the same as y = x - 2 which is the equation of a straight line. A single straight line cannot have a vertex.
Without an equality sign the given expression can't be considered to be an equation
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
y=x2-10x+30=(x-5)2-25+30=(x-5)2+5
The equation is linear and so has no vertex.
x2+8= y This equation represents a function. It will be a parabola with the vertex at (0,8). You can easily graph this on a graphing calculator or from prior knowledge. You know the basic graph of y=x2 with vertex (0,0) and opens upwards on the y-axis. From the equation, you simply shift the vertex vertically up 8 so the new vertex is (0,8) This represents a function because for every x value there is one y value.
The vertex form is y = (x - 4)2 + 13
y = x +1 is the equation of a straight line and so has no vertex.
The given equation is not that of a parabola.
y2-3x2+6x+6y= 18 is in standard form. The vertex form would be (y+3)2/24 - (x-1)2/8 = 1
The vertex form of this function.X2 + 22X = 31Halve the linear term ( 22 ) square it and add it to both sides.X2 + 22X + 121 = 31 + 121Factor the left side of this equation and gather terms on the right side.(X + 11)2 = 152(X + 11)2 - 152 = 0===================vertex form of this function(- 11, - 152 )===========Vertex
The vertex of the positive parabola turns at point (-2, -11)
A quadratic equation.