1 + 11x =1 + 11x (this is the simplest solution you can make with available information)
11x(2x - 1) = 0 so either 11x = 0 or x = ½
If you mean: y = 11x+1 then the y intercept is 1 and the slope is 11
12x - 5 = 11x + 5(1) add 5 to both sides:12x - 5 + 5 = 11x + 5 + 512x = 11x + 10(2) next subtract 11x from both sides:12x - 11x = 11x - 11x + 10x = 10
-7+11x = 9-5x 11x+5x = 9+7 16x = 16 x = 1
1 + 11x =1 + 11x (this is the simplest solution you can make with available information)
(11x - 1)(11x - 1) (11x - 1)2
(11x-1)(11x-1)
The "difference of squares" has a formula. (11x + 1)(11x - 1)
-11x-1 = -10x-8 -11x+10 = -8+1 -1x = -7 x = 7
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
x2 = 11x - 10 ∴ x2 - 11x + 10 = 0 ∴ (x - 10)(x - 1) = 0 ∴ x ∈ {1, 10}
11x(2x - 1) = 0 so either 11x = 0 or x = ½
If you mean: y = 11x+1 then the y intercept is 1 and the slope is 11
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
12x - 5 = 11x + 5(1) add 5 to both sides:12x - 5 + 5 = 11x + 5 + 512x = 11x + 10(2) next subtract 11x from both sides:12x - 11x = 11x - 11x + 10x = 10
-7+11x = 9-5x 11x+5x = 9+7 16x = 16 x = 1