It is 3 + 54c.
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3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
17-3= 4c+3c c=2
2ab - 6ac + 3b - 9c = 2a(b - 3c) + 3(b - 3c) = (2a + 3)(b - 3c).
The solution (not sum) to the equation 21 = 3c + 6 is as follows:21 = 3c + 621 - 6 = 3c + 6 - 615 = 3c3c = 153c/3 = 21/3c = 7
4c+2 = 3c+9 4c-3c = 9-2 c = 7