we can give a general expression:
and limit is consider in only positive direction since ln eista for positives only
nx is called the hyper power of x
and when x tends to zero the general case is
if n is a odd number then answer is zero
if n is a even number it is 1
since consider the following example
xx = ex ln(x) and when x tend s to zero the value is 1.
let it is 3x = e x2 ln(x) whose value is zero
similarly for other cases
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Limit as x tends to ∞: x/e^xAs you can see, as x approaches infinity, the sum becomes ∞/∞. Now we use l'Hospitals rules.d/dx(x) = 1 (Derivative)d/dx(e^x) = e^x (Derivative)therefore, the sum can be written as lim x tends to ∞ 1/e^xNow as x approaches infinity, the sum = 1/∞ = 0Therefore, lim x tends to infinity: x/e^x = 0
If x --> 0+ (x tends to zero from the right), then its logarithm tends to minus infinity. On the other hand, x --> 0- (x tends to zero from the left) makes no sense, at least for real numbers, because the logarithm of negative numbers is undefined.
Infinity
One way to find a vertical asymptote is to take the inverse of the given function and evaluate its limit as x tends to infinity.
x can go to + or - infinity. f(x) is limited from + 1/2 to - 1/2.