It is y = 0
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
The domain is (-infinity, infinity) The range is (-3, infinity) and the asymptote is y = -3
if you mean e to the x power times log of x, it is e to the x divided by x
Yes, the asymptote is x = 0. In order for logarithmic equation to have an asymptote, the value inside log must be 0. Then, 5x = 0 → x = 0.
Answer: no [but open to debate] ((x-1)(x-2)(x+2))/(x-3) (x^2-3x+2)/(x-2)(x+2) Asymptote missing, graph it, there is no Asymptote because the (x-2)(x+2) can be factored out. yes
The graph of an exponential function f(x) = bx approaches, but does not cross the x-axis. The x-axis is a horizontal asymptote.
-1
integral of e to the power -x is -e to the power -x
what symbol best describes the asymptote of an exponential function of the form F(x)=bx
Yes. Take the functions f(x) = log(x) or g(x) = ln(x) In both cases, there is a vertical asymptote where x = 0. Because a number cannot be taken to any power so that it equals zero, and can only come closer and closer to zero without actually reaching it, there is an asymptote where it would equal zero. Note that transformations (especially shifting the function left and right) can change the properties of this asymptote.
y = x / (x^2 + 2x + 1) The horizontal asymptote is y = 0