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A set of ordered pairs (x, y) where x and y are real numbers.

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Q: What is a subset of R x R?
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Related questions

What is the domain of y equals ln x?

In elementary mathematics, any subset of R+, the non-negative real numbers.


If a set A is equivalent to a subset of B and B is equivalent to a subset of A then show that A is equivalent to B?

This problem can be modeled and tested quite easily. Set A can be [X,Y], subset B [X,Y], and subset A [X,Y]. Therefore A and B are equivalent.


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It depends on what x and f are.


What is the domain of x squared plus 5x-20?

-15


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The set X is a proper subset of Y if Xcontains none or more elements from Y and there is at least one element of Y that is not in X.


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Let x be in A intersect B. Then x is in A and x is in B. Then x is in A.


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Π R.l (R) ⊆ Π S.l (S)


Is z a subset of x?

It depends on what z and x are. Since you did not share that information, it is not possible to give a sensible answer.


Is a vertical line a relation in math?

Yes, you can consider it a relation between the points on the x-axis, and the points on the y-axis. In fact, ANY subset of R squared (in other words, any subset of the points on a plane), including the empty set, sets that contain single points, and larger sets, can be considered a relation in R squared (i.e., two sets of real numbers).


Prove AnB subset A subset AUB?

I shall answer this under the assumption that 'n' means intersection. Recall the definitions of intersection and union: 1) x is an element of AnB if and only if x is an element of A and x is an element of B 2) x is an element of AUB if and only if x is an element of A or x is an element of B and recall that 3) X is an (improper) subset of Y if and only if every element of X is an element of Y Thus, if x is an element of AnB, then x is an element of A and an element of B, so it clearly is an element A (law of simplification in logic). This implies AnB is a subset of A. Now if x is an element of A, it is certainly an element of A or an element of B (law of addition in logic), and therefore x is an element of AUB. There are other ways of answering this based on axiomatic approaches.