In elementary mathematics, any subset of R+, the non-negative real numbers.
The universal subset is the empty set. It is a subset of all sets.
A number does not have a subset.
surface area=2 x pi x r² + 2 x pi x r x h volume = pi x r² x h
pi x r x r x h (where r is radius of base, he is height)
In elementary mathematics, any subset of R+, the non-negative real numbers.
This problem can be modeled and tested quite easily. Set A can be [X,Y], subset B [X,Y], and subset A [X,Y]. Therefore A and B are equivalent.
It depends on what x and f are.
-15
The set X is a proper subset of Y if Xcontains none or more elements from Y and there is at least one element of Y that is not in X.
Let x be in A intersect B. Then x is in A and x is in B. Then x is in A.
any interval subset of R is open and closed
Electromagnetic waves have x-rays as a subset of their range.
Π R.l (R) ⊆ Π S.l (S)
It depends on what z and x are. Since you did not share that information, it is not possible to give a sensible answer.
Yes, you can consider it a relation between the points on the x-axis, and the points on the y-axis. In fact, ANY subset of R squared (in other words, any subset of the points on a plane), including the empty set, sets that contain single points, and larger sets, can be considered a relation in R squared (i.e., two sets of real numbers).
I shall answer this under the assumption that 'n' means intersection. Recall the definitions of intersection and union: 1) x is an element of AnB if and only if x is an element of A and x is an element of B 2) x is an element of AUB if and only if x is an element of A or x is an element of B and recall that 3) X is an (improper) subset of Y if and only if every element of X is an element of Y Thus, if x is an element of AnB, then x is an element of A and an element of B, so it clearly is an element A (law of simplification in logic). This implies AnB is a subset of A. Now if x is an element of A, it is certainly an element of A or an element of B (law of addition in logic), and therefore x is an element of AUB. There are other ways of answering this based on axiomatic approaches.