0
n=1 a(1) = 0.001
n=2 a(2) = 0.012
n=3 a(3) = 0.144
n=4 a(4) = 1.728
n=5 a(5) = 20.736
....
n=k a(k) = (12^(k-1))/1000
let n = k+1
a(k+1) = 12^(k)/1000
12(ak) = a(k+1)
12(12^k-1)/1000 = 12^k/1000
the 12 gets absorbed here.
12^(k-1+1)/1000 = 12^k/1000
Valid for k and k+1
therefore our equation
A(n) = 12^(n-1)/1000, n(greater than or equal to) 1
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In order to answer the question is is necessary to know what the explicit formula was. But, since you have not bothered to provide that information, the answer is .
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No.
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In order to answer the question is is necessary to know what the explicit formula was. But, since you have not bothered to provide that information, the answer is .
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The sequence is neither arithmetic nor geometric.
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Yes, that's what a geometric sequence is about.
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a sequence of shifted geometric numbers
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Algebra words that start with g?
· Geometric Sequence (geometric progression) - a sequence of numbers in which each term is obtained by multiplying the preceding term by the same number (common ratio). The following is a geometric progression: 1, 2, 4, 8, 16, 32… The common ratio for this geometric progression is 2.
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Since there is only one number, there is no sensible answer.
What does geometric sequence?
You mean what IS a geometric sequence? It's when the ratio of the terms is constant, meaning: 1, 2, 4, 8, 16... The ratio of one term to the term directly following it is always 1:2, or .5. So like, instead of an arithmetic sequence, where you're adding a specific amount each time, in a geometric sequence, you're multiplying by that term.
