When n=30, 3n-1 = 89 .
16
3n+7
What is the 2nd term of 3n-2?
1+3n
When n=30, 3n-1 = 89 .
Just plug in 30 for n in 3n-1. The answer is 89.
16
(3n)(3n-1) = 3n * 3n - 3n * 1 Now, perform the multiplication: (3n * 3n) = 9n^2 (3n * 1) = 3n So, (3n)(3n-1) simplifies to: 9n^2 - 3n
3n+7
3n(n+1] + 5 is the nth term
What is the 2nd term of 3n-2?
123456789 * * * * * The nth term is 3n
The Series has the formula 3n + 1/2(n - 1)(n - 2) = 3n + 1/2(n2 - 3n + 2) which simplifies to, 1/2(n2 +3n + 2)
1+3n
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.