tn = n2 + 9, n = 1,2,3,...
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
Un = 5n - 2
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
Un = 5n - 2
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
It is: 5n+3 and so the next term is 28
The next term is 45 because the numbers are increasing by increments of 3 5 7 9 and then 11
1,7,13,19
It is: 25-7n
18,23,28,33,... #1 is 18 #2 is 23 A difference of '5' Hence we can write '5n + x = 18 Where 'n' equals '1' Hence 5(1) + x = 18 5 + x = 18 Hence x = 18 - 5 = 13 So nth term is 5n + 13 NB Verification; does it work for the 4th term 5(4)+ 13 = 20 + 13 = 33 Which is true from above list.
Un = 25 - 7n
The sequence 3, 8, 13, 18, 23, 28 increases by 5 each time. This indicates a linear pattern. The nth term can be expressed as ( a_n = 3 + 5(n - 1) ), which simplifies to ( a_n = 5n - 2 ). Thus, the nth term of the sequence is ( 5n - 2 ).
To find the nth term of the sequence 4, 10, 18, 28, 40, we first identify the pattern in the differences between consecutive terms: 6, 8, 10, and 12. The second differences are constant at 2, indicating a quadratic sequence. The nth term can be expressed as ( a_n = n^2 + n + 2 ). Thus, the nth term of the sequence is ( n^2 + n + 2 ).
If you mean: 6 12 18 24 then the nth term is 6n
If the term number is n, then the nth term is 10(n-1) +8.
To find the nth term of the sequence 3, 8, 13, 18, I first identified the pattern in the differences between consecutive terms: 5, 5, 5. Since these differences are constant, the sequence is linear. The nth term can be expressed in the form ( a_n = an + b ). By using the first term (3) and the common difference (5), I derived the formula: ( a_n = 5n - 2 ).
The sequence given is -2, -8, -18, -32, -50. To find the nth term, we first observe the differences between consecutive terms: -6, -10, -14, -18, which show that the second differences are constant at -4. This indicates that the nth term can be expressed as a quadratic function. By fitting the sequence to the form ( a_n = An^2 + Bn + C ), we find that the nth term is ( a_n = -2n^2 + 2n - 2 ).
The nth term is 18 -3n and so the next term will be 3
The nth term of the sequence is (n + 1)2 + 2.