(4x + -4x) + (8y + 2y) = 20 + -30
⇒ 10y = -10
⇒ y = -1
⇒ (4x - -16x) + (8y - 8y) = 20 - -120
⇒ 20x = 140
⇒ x = 7
Solution x = 7, y = -1
Alternatively, to find x, now that y is known to be -1:
Substitute y = -1 into equation 1. to give:
4x + 8(-1) = 20
⇒ 4x -8 = 20
⇒ 4x = 28
⇒ x = 7
The solution can be checked y substituting the values found for x and y in to equation 2. and checking it is the correct value:
-4x + 2y = -4(7) + 2(-1)
= -28 + -2
= -30
as required, so the solution is correct.
Solving the above simultaneous equations by means of the elimination method works out as x = 2 and y = 3
the first step in solving the equation is to subtract the nine from the three. you will get negative 6.
-2=4r+s s=-4r-2 or s=-(4r+2)
2048
it's not possible. try using a calculator. the answer will always be 4
Solving by the elimination method: x = 7 and y = 2
Solving by elimination: p = 3 and q = -2
No. Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
By elimination: x = 3 and y = 0
Solving these simultaneous equations by the elimination method:- x = 1/8 and y = 23/12
(2,-2)
Solving the above simultaneous equations by means of the elimination method works out as x = 2 and y = 3
Yes and it works out that x = 3 and y = 4
Double first equation: 2x + 2y = 4 Subtract this from second equation giving 5y = 5 so y = 1 and x = 1
4
y=16 x= -4
x = 5, y = -2