(3n)(3n-1) = 3n * 3n - 3n * 1 Now, perform the multiplication: (3n * 3n) = 9n^2 (3n * 1) = 3n So, (3n)(3n-1) simplifies to: 9n^2 - 3n
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
Is it a. 3n square and 3n ans. 3n b. 3n *2 and 3n ans.3n ans. 3n for both!!
No. 3n is not a factor of 3n + 7.
No. 3n is not a factor of 3n + 7.
The GCF is 3n.
25-3n = 22
No. 3n isn't a factor of 3n + 7. The GCF of 3n + 7 and 9n is 1.
3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.
3n^4 divided by 3n^3 = n
3n+2+3n+2=6n+4
This can be solved by grouping all terms with "n" in them on one side of the equation, and all other terms on the opposite side, then adding together like terms, and dividing both sides by the remaining coefficient of "n": n - 16 = 2n + 12 + 3n ∴ n - 2n - 3n = 12 + 16 ∴ -4n = 28 ∴ n = -7