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-k = -1*k, so the coefficient is minus 1

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Q: What is the coefficient of k in -k?
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What is the answer to k plus 9k?

The implied coefficient in front of ' K ' = 1 so, 1K + 9K = 10K ----------


What is the coefficient of the squared term in the parabola's equation when the vertex is at -2 -3 and the point -1 -5 is on it?

A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (-2, -3), and a point on it is (-1, -5) → -5 = a(-1 - -2)² + -3 → -5 = a(1)² - 3 → -5 = a - 3 → a = -2 → The coefficient of the x² term is -2.


What is the coefficient of the squared term in the parabola's equation when the vertex is at 2 -1 and the point 5 0 is on it?

A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (2, -1), and a point on it is (5, 0) → 0 = a(5 - 2)² + -1 → 0 = a(3)² -1 → 1 = 9a → a = 1/9 → The coefficient of the x² term is 1/9


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In mathematics, "big B" can refer to various concepts depending on the context. If you are referring to the binomial coefficient, which is denoted as "n choose k" or "nCk," it represents the number of ways to choose k items from a set of n items. The formula to calculate the binomial coefficient is n! / (k! * (n-k)!), where "!" denotes factorial. If "big B" refers to another concept or symbol, please provide more context for a more specific explanation.


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What is the answer to k plus 9k?

The implied coefficient in front of ' K ' = 1 so, 1K + 9K = 10K ----------


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What is the coefficient of the squared term in the parabola's equation when the vertex is at -2 -3 and the point -1 -5 is on it?

A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (-2, -3), and a point on it is (-1, -5) → -5 = a(-1 - -2)² + -3 → -5 = a(1)² - 3 → -5 = a - 3 → a = -2 → The coefficient of the x² term is -2.


What is the coefficient of the squared term in the parabola's equation when the vertex is at 2 -1 and the point 5 0 is on it?

A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (2, -1), and a point on it is (5, 0) → 0 = a(5 - 2)² + -1 → 0 = a(3)² -1 → 1 = 9a → a = 1/9 → The coefficient of the x² term is 1/9