To find the smallest value of k when 882k is a cube, we need to factor out the cube from 882k. The prime factorization of 882 is 2 x 3^2 x 7^2. For 882k to be a cube, we need to find the smallest value of k such that the exponent of each prime factor in the prime factorization of 882k is a multiple of 3. Therefore, the smallest value of k would be 2^2 x 3 x 7 = 84.
33 = 81 63 = 216 93 = 729 and 123 = 1728
The cube root of this number is one more than the smallest prime
k = 98. In the prime factorization (in power format) of a perfect cube, every prime must be to the power of a multiple of 3. 756 = 2^2 x 3^3 x 7 Thus the smallest perfect cube that is a multiple of 756 is 2^3 × 3^3 × 7^3; to obtain this need to multiply 756 by 2^1 × 3^0 × 7^2 = 98 Thus the smallest k to make 756k a perfect prime is k = 98.
6
2^6 = 64 The cube root is 2^2, or 4
The prime factorization for 125 is:5 X 5 x 5125 is the cube of 55x5x5
The cube root of 1728 is: 121728 cubed is: 5,159,780,352
25
1728 is even so it cannot have an odd cube root.
the cube root of 1728 is 12
Because 123 = 1728
If a factor appears 3 times, you get this factor (only once) times the cube root of a smaller number (the original number divided by the factor cubed).
12
Volume of cube: 12*12*12 = 1728 cubic inches
1728 cubic inches
To find the smallest value of k when 882k is a cube, we need to factor out the cube from 882k. The prime factorization of 882 is 2 x 3^2 x 7^2. For 882k to be a cube, we need to find the smallest value of k such that the exponent of each prime factor in the prime factorization of 882k is a multiple of 3. Therefore, the smallest value of k would be 2^2 x 3 x 7 = 84.