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What is the smallest value of k when 882k is a cube?
Factor the number 882, until you get prime factors. See what prime factors are missing to complete a cube (each prime number has to be to the power 3, 6, etc.). Multiply those missing factors, to get "k".
What are the first 4 cube numbers that are also multiples of 3?
33 = 81 63 = 216 93 = 729 and 123 = 1728
The cube root of this number is one more than the smallest prime?
The cube root of this number is one more than the smallest prime
What is the smallest integer k such that 756k is a perfect cube?
k = 98. In the prime factorization (in power format) of a perfect cube, every prime must be to the power of a multiple of 3. 756 = 2^2 x 3^3 x 7 Thus the smallest perfect cube that is a multiple of 756 is 2^3 × 3^3 × 7^3; to obtain this need to multiply 756 by 2^1 × 3^0 × 7^2 = 98 Thus the smallest k to make 756k a perfect prime is k = 98.
Which 1-digit number is neither a prime nor a square nor a cube?
6
What is the cube root of 64 using prime factorization?
2^6 = 64 The cube root is 2^2, or 4
What is the prime factorization for 125?
The prime factorization for 125 is:5 X 5 x 5125 is the cube of 55x5x5
cube root of 15625 prime factorization?
25
What is the cube of 1728?
The cube root of 1728 is: 121728 cubed is: 5,159,780,352
What is the odd cube number of 1728?
1728 is even so it cannot have an odd cube root.
How do you find the cube root of 2330 using prime factorization?
If a factor appears 3 times, you get this factor (only once) times the cube root of a smaller number (the original number divided by the factor cubed).
What is a number cubed is 1728 what is the number?
the cube root of 1728 is 12
How is cube root 1728 equals 12?
Because 123 = 1728
Cube root of 1728?
12
What number multiplied by itself 3 times is 1728?
To find the number that, when multiplied by itself three times, equals 1728, you need to calculate the cube root of 1728. The cube root of 1728 is 12, since 12 × 12 × 12 = 1728. Therefore, the number is 12.
Is 2700 a perfect cube?
No, 2700 is not a perfect cube. A perfect cube is a number that can be expressed as the cube of an integer. The prime factorization of 2700 is (2^2 \times 3^3 \times 5^2), and since not all prime factors have exponents that are multiples of three, it cannot be a perfect cube.
What number times itself three times equals 1728?
To find the number that, when multiplied by itself three times, equals 1728, we need to calculate the cube root of 1728. The cube root of 1728 is 12, since (12 \times 12 \times 12 = 1728). Thus, the number you are looking for is 12.
