The formula for finding the derivative of a log function of any "a" base is
(dy/dx)log base a (x) = 1/((x)ln(a))
If we're talking about base "e" (natural logs) the answer is 1/(x-2)
I think you're asking for the derivative of y = logx2. It's (-logx2)/(x(lnx)).
Chat with our AI personalities
-1/x2
-4/x2
The antiderivative of x2 + x is 1/3x3 + 1/2x2 + C.
0
All it means to take the second derivative is to take the derivative of a function twice. For example, say you start with the function y=x2+2x The first derivative would be 2x+2 But when you take the derivative the first derivative you get the second derivative which would be 2