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The product rule states: d/dx uv = vdu/dx + udv/dx
It is not quite clear what your denominator is:
- "over 1 + (x squared)": d/dx (x/1+x2)
= (1 + x2)-1 d/dx x + x d/dx (1 + x2)-1
= (1 + x2)-1 + x -2x (1 + x2)-2
= (1 + x2)-2 (1 + x2 - 2x2)
= (1 - x2) / (1 + x2)2
- "over (1 + x) [all] squared": d/dx (x/(1+x)2)
= (1 + x)-2 d/dx x + x d/dx (1 + x)-2
= (1 + x)-2 + x -2 (1 + x)-3
= (1 + x)-3 (1 + x - 2x)
= (1 - x)/(1 + x)3
If you prefer, you can use the quotient rule: d/dx (u/v) = (v du/dx - udv/dx) / v2
What else can I help you with?
1 squared plus 1 squared plus 2 squared plus 3 squared plus 5 squared plus 8 squared equals?
104
What is 1 squared plus 1 squared plus 1 squared plus one squared plus one squared plus one squared?
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5
What is 1 squared plus 3?
1 squared (1x1) +3=4
What is 2 over x plus 1 over x squared?
2/x + 1/x2 = (2x+1)/x2
What is the Derivative of 500 ln x plus 1?
the derivative of ln x = x'/x; the derivative of 1 is 0 so the answer is 500(1/x)+0 = 500/x
What is the derivative of 1 over 2x?
It is -1 over x-squared.
What is the anti-derivative of x squared plus 3?
∫ (x2+3) = ∫x2 + ∫3(1/3)X3 + 3X + C
1 squared plus 1 squared plus 2 squared plus 3 squared plus 5 squared plus 8 squared equals?
104
What is the differentiation of sin x over 1 plus cosx?
The derivative is 1/(1 + cosx)
What is 1 squared plus 1 squared plus 1 squared plus one squared plus one squared plus one squared?
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5
What is the integral of 1 over x squared plus 1?
arctan(x)
What is d-squared plus 3d plus 9 over 4 simplifyed?
it would be 1 fourth multiplied by quanity d squared plus 3d plus 9 (1/4)(d2 + 3d + 4)
What is the derivative of the square root of one minus x squared?
f(x) = (1 - x^(2) ^(1/2) Let y= (1 - x^(2)) ^(1/2) Use Chain Rule dy/dx = dy/du X du/dx Let u = 1 - x^(2) Hence y = u^(1/2) dy/du = (1/2)u^(-1/2) du/dx = -2x Hence dy/dx = dy/du X du/dx = (1/2)u^(-1/2) X ( -2x) dy/dx = (1/2)u( 1 -x^(2)^(-1/2) X ( -2x) Tidying up dy/dx = (-2x/(2(1 - x^(2))^(1/2)) dy/dx = -x/ [(1 - x^(2)]^(1/2)
What is the derivative of x over the square root of x squared plus one?
Express as, d/dx[(X)(X2 + 1)1/2 Use the chain rule here after distribution f'(x)g(x) * g'(x) =================================I would leave it at this
What 2 integers squared equal 65?
1 squared plus 8 squared or 4 squared plus 7 squared
How do you differentiate y equal to one third x cubed minus 3x squared plus 8x plus one third?
The derivative of y = 1/3 x3 - 3x2 + 8x + 1/3 is x2 - 6x + 8. You can determine this for yourself by the rules. The derivative of a constant (e.g. 1/3) is 0. The derivative of xn for positive n (actually all nonzero n) is nxn-1. And if the derivative of f(x) is f'(x), then the derivative of k f(x) is k f'(x). Put all these together and you get the above result.
How do you simplify x brackets x plus 1 brackets squared?
x[x+1] squared Simplified is, to my knowledge, x squared plus ( x + 1) squared
