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Assuming this is the x-y plane.
Create the right-triangle (-4,3), (-4,-2), (-2,-2)
This is a triangle with sides of 5, 2 and H, the distance between the two endpoints...
using Pythagoras's theorem, we get
H2 = 52 + 22
H2 = 25 + 4
H2 = 29
H = sqrt(29)
This could just as easily have been done with the right triangle (-4,3), (-2,3), (-2,-2)
You can also use the Distance Formula.
It is d2 = (x2 - x1)2 + (y2 - y1)2 where d2 is the distance between the two points squared (you can also say the distance between the two points is the square root of that equation, but as I didn't know how to put the square root sign, I just said d2
In this case, it would be:
d2 = (-4 - (-2))2 + (3 - (-2))2
d2 = (-2)2 + (5)2
d2 = 4 + 25 = 29
d = square root of 29
It doesn't matter which point you use for x1 and y1 as long as they come from the same point. Also the distance formula comes from the Pythagorean Theorem so it's not too important which one you use.
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Find the distance between the following pairs of points Round your answer to the nearest tenth 4 and -3 and the second is 2 and 4?
P1 = (4, -3)P2 = (2, 4)(Distance)2 = (delta-x)2 + (delta-y)2(Distance)2 = (4 - 2)2 + (-3 - 4)2 = (2)2 + (-7)2 = 4 + 49 = 53Distance = sqrt(53) = 7.3 (rounded)
Find the distance between (-4 2) and (-7 -6). in units?
The distance between the points of (4, 3) and (0, 3) is 4 units
What is the distance between two points -3 7 and -6 4?
(-3-(-6))2 + (7-4)2 = 18 and the square root of this is the distance between the two points
What is the distance between the points 3 and -4 and 3 and -8 and 1?
Distance formula: square root of (x1-x2)2+(y1-y2)2
Distance between 4 -3 and 2 4?
If these are Cartesian coordinates in the standard form (x,y), the distance is 7.28 units, roughly.
What is the distance between the points -4 3 and 3 -1?
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
How can you find the distance between two numbers on a number line?
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
Find the distance between the following pairs of points Round your answer to the nearest tenth 4 and -3 and the second is 2 and 4?
P1 = (4, -3)P2 = (2, 4)(Distance)2 = (delta-x)2 + (delta-y)2(Distance)2 = (4 - 2)2 + (-3 - 4)2 = (2)2 + (-7)2 = 4 + 49 = 53Distance = sqrt(53) = 7.3 (rounded)
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between the two points 7 7 and 4 3?
Use Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((4 - 7)^2 + (3 - 7)^2) = √((-3)^2 + (-4)^2) = √(9 + 16) = √25 = 5 units.
Find the distance between (-4 2) and (-7 -6). in units?
The distance between the points of (4, 3) and (0, 3) is 4 units
What is the distance between points 2 4 and 6 3?
Using Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - 2)^2 + (3 - 4)^2) = √(16 + 1) = √17 ≈ 4.12
What is the distance between (3 5) and (3 -4)?
It is the square root of (-3-0)2+(-4-0)2 = 5
What is the distance between -8 and plus 4 on a number line?
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 There is a distance of 12.
What is the distance between the points -1 -9 and 4 -2?
Points: (-1, -9) and (4, -2) Distance: (-1-4)2+(-9--2)2 = 74 and the square root of this is the distance which is about 8.602 to 3 decimal places
What is the distance between the points (-5 2) and (4 9)?
Points: (-1, -9) and (4, -2) Distance: (-1-4)2+(-9--2)2 = 74 and the square root of this is the distance which is about 8.602 to 3 decimal places
What is the distance between the origin -3 and -4?
It is the square root of (-3-0)2+(-4-0)2 = 5
