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Assuming this is the x-y plane.
Create the right-triangle (-4,3), (-4,-2), (-2,-2)
This is a triangle with sides of 5, 2 and H, the distance between the two endpoints...
using Pythagoras's theorem, we get
H2 = 52 + 22
H2 = 25 + 4
H2 = 29
H = sqrt(29)
This could just as easily have been done with the right triangle (-4,3), (-2,3), (-2,-2)
You can also use the Distance Formula.
It is d2 = (x2 - x1)2 + (y2 - y1)2 where d2 is the distance between the two points squared (you can also say the distance between the two points is the square root of that equation, but as I didn't know how to put the square root sign, I just said d2
In this case, it would be:
d2 = (-4 - (-2))2 + (3 - (-2))2
d2 = (-2)2 + (5)2
d2 = 4 + 25 = 29
d = square root of 29
It doesn't matter which point you use for x1 and y1 as long as they come from the same point. Also the distance formula comes from the Pythagorean Theorem so it's not too important which one you use.
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Find the distance between the following pairs of points Round your answer to the nearest tenth 4 and -3 and the second is 2 and 4?
P1 = (4, -3)P2 = (2, 4)(Distance)2 = (delta-x)2 + (delta-y)2(Distance)2 = (4 - 2)2 + (-3 - 4)2 = (2)2 + (-7)2 = 4 + 49 = 53Distance = sqrt(53) = 7.3 (rounded)
Find the distance between (-4 2) and (-7 -6). in units?
The distance between the points of (4, 3) and (0, 3) is 4 units
What is the distance between two points -3 7 and -6 4?
(-3-(-6))2 + (7-4)2 = 18 and the square root of this is the distance between the two points
What is the distance between the points 3 and -4 and 3 and -8 and 1?
Distance formula: square root of (x1-x2)2+(y1-y2)2
Distance between 4 -3 and 2 4?
If these are Cartesian coordinates in the standard form (x,y), the distance is 7.28 units, roughly.
How can you find the distance between two numbers on a number line?
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
Find the distance between the following pairs of points Round your answer to the nearest tenth 4 and -3 and the second is 2 and 4?
P1 = (4, -3)P2 = (2, 4)(Distance)2 = (delta-x)2 + (delta-y)2(Distance)2 = (4 - 2)2 + (-3 - 4)2 = (2)2 + (-7)2 = 4 + 49 = 53Distance = sqrt(53) = 7.3 (rounded)
Find the distance between (-4 2) and (-7 -6). in units?
The distance between the points of (4, 3) and (0, 3) is 4 units
What is the distance between (3 5) and (3 -4)?
It is the square root of (-3-0)2+(-4-0)2 = 5
What is the distance between the points -1 -9 and 4 -2?
Points: (-1, -9) and (4, -2) Distance: (-1-4)2+(-9--2)2 = 74 and the square root of this is the distance which is about 8.602 to 3 decimal places
What is the distance between the points (-5 2) and (4 9)?
Points: (-1, -9) and (4, -2) Distance: (-1-4)2+(-9--2)2 = 74 and the square root of this is the distance which is about 8.602 to 3 decimal places
What is the distance from point M (3 2) to point N (3 4)?
The distance is 2, along the x-value line x=3 i.e. (3, y).
What is the distance between two points -3 7 and -6 4?
(-3-(-6))2 + (7-4)2 = 18 and the square root of this is the distance between the two points
What is the distance between the points 3 and -4 and 3 and -8 and 1?
Distance formula: square root of (x1-x2)2+(y1-y2)2
Which expression gives the distance between the points 46 and 7-3?
If you mean: (4, 6) and (7, -3) then it is:- Distance is the square root of (4-7)^2+(6--3)^2 = 9.487 rounded to 3 decimal places
Find the distance between 8 -4 and 2 15?
(8-2)2+(-4-15)2 = 397 and the square root of this is the distance which is 19.925 rounded to 3 decimal places
What is the distance between this pair of points 0 4 and -4 6?
Distance = sqrt [(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt [(6 - 4)2 + (- 4 - 0)2]Distance = sqrt [(2)2 + (- 4)2]Distance = sqrt(4 + 16)Distance = sqrt(20)==============
