-8i
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6+2i
(-2 + 3i) + (-1 - 2i) = -2 + 3i - 1 - 2i = -2 - 1 + 3i - 2i = -3 + i
10 + 6i and 7 + 2i = 10 + 6i + 7 + 2i = 17 + 8i
It is imaginary; we denote sqrt of -1 = i square root (-4) = ± 2i
f(x)=x3-3x2-5x+39=(x+3)(x2-6x+13) It has three roots. One of which is x=-3. Using the quadratic equation: x = (6 +/- √(-16))/2 x = (6 +/- 4i)/2 = (3 +/- 2i) so, x=-3, x=3+2i, or x=3-2i