They are: 6 15 24 33 and 42
5 first terms in n²+3
5, 11, 17, 23, 29
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
Expressed in terms of n, the nth term is equal to 7n - 2.
To find the nth term in this pattern, we first need to identify the pattern itself. The differences between consecutive terms are 7, 9, and 11 respectively. This indicates that the pattern is increasing by 2 each time. Therefore, the nth term can be found using the formula: nth term = 5 + 2(n-1), where n represents the position of the term in the sequence.
5 first terms in n²+3
5, 11, 17, 23, 29
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
To find the nth term of the linear sequence -9, -5, -1, we first identify the common difference between the terms. The difference between consecutive terms is 4. The first term (a) is -9, so the nth term can be expressed as ( a_n = -9 + (n-1) \cdot 4 ), which simplifies to ( a_n = 4n - 13 ).
nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
5, 8, 11, 14 and 17.
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
To find the nth term of the quadratic sequence 3, 8, 15, 24, 35, we first identify the differences between the terms: 5, 7, 9, 11, which indicates a second difference of 2. This suggests the sequence can be represented by a quadratic formula of the form ( an^2 + bn + c ). By solving the equations formed using the first few terms, we find the nth term to be ( n^2 + 2n ). Thus, the nth term of the sequence is ( n^2 + 2n ).
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
Expressed in terms of n, the nth term is equal to 7n - 2.
To find the Nth term of the sequence 5, 8, 13, 20, 29, we first observe the differences between consecutive terms: 3, 5, 7, and 9, which increases by 2 each time. This suggests the sequence is quadratic. The Nth term can be expressed as ( a_n = n^2 + 4n + 1 ), or more simply as ( a_n = n^2 + 3n + 5 ), where ( n ) starts from 1.