5 first terms in n²+3
5, 11, 17, 23, 29
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
Expressed in terms of n, the nth term is equal to 7n - 2.
To find the nth term in this pattern, we first need to identify the pattern itself. The differences between consecutive terms are 7, 9, and 11 respectively. This indicates that the pattern is increasing by 2 each time. Therefore, the nth term can be found using the formula: nth term = 5 + 2(n-1), where n represents the position of the term in the sequence.
5 first terms in n²+3
5, 11, 17, 23, 29
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
5, 8, 11, 14 and 17.
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
Expressed in terms of n, the nth term is equal to 7n - 2.
First look for the difference between the terms, for example the sequence: 5, 8, 11, 14... has a difference of 3. This means the sequence follows the 3 times table - i.e. 3n Now since we need the first term to be 5 we add 2 to our rule to make it work. So the nth term of this sequence is 3n + 2.
To find the nth term in this pattern, we first need to identify the pattern itself. The differences between consecutive terms are 7, 9, and 11 respectively. This indicates that the pattern is increasing by 2 each time. Therefore, the nth term can be found using the formula: nth term = 5 + 2(n-1), where n represents the position of the term in the sequence.
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
The nth term is: 5-2n