5 first terms in n²+3
5, 11, 17, 23, 29
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
Expressed in terms of n, the nth term is equal to 7n - 2.
5 first terms in n²+3
5, 11, 17, 23, 29
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
32, 60, 88, 116, 144
nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
5, 8, 11, 14 and 17.
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
Expressed in terms of n, the nth term is equal to 7n - 2.
First look for the difference between the terms, for example the sequence: 5, 8, 11, 14... has a difference of 3. This means the sequence follows the 3 times table - i.e. 3n Now since we need the first term to be 5 we add 2 to our rule to make it work. So the nth term of this sequence is 3n + 2.
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
The nth term is: 5-2n