There are two ways to say the general rule. They both mean exactly
the same thing, and they both generate the same sequence:
1). Starting with 15, each new term is 3 less than the one before it.
2). The nth term of the sequence is [ 18 - 3n ] or [ 3 times (6 - n) ].
The sequence 216 12 23 is neither arithmetic nor geometric.
12, 6, 0, -6, ...
7
No, geometric, common ratio 2
It appears to be -6
The sequence 216 12 23 is neither arithmetic nor geometric.
No, the sequence 3, 6, 12, 24 is not an arithmetic sequence. In an arithmetic sequence, the difference between consecutive terms is constant. Here, the differences are 3 (6-3), 6 (12-6), and 12 (24-12), which are not the same. This sequence is actually a geometric sequence, as each term is multiplied by 2 to get the next term.
It is neither.
12, 6, 0, -6, ...
A(1) = 12A(4) = 3 A(10) = -15.
It is -148.
7
No, geometric, common ratio 2
It appears to be -6
No it is not.U(2) - U(1) = 6 - 2 = 4U(3) - U(2) = 18 - 6 = 12Since 4 is different from 12, it is not an arithmetic sequence.
The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.
The sequence in the question is NOT an arithmetic sequence. In an arithmetic sequence the difference between each term and its predecessor (the term immediately before) is a constant - including the sign. It is not enough for the difference between two successive terms (in any order) to remain constant. In the above sequence, the difference is -7 for the first two intervals and then changes to +7.