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How many triangles exist with the given side lengths 4m 4m 7m?
To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
What is the volume of a rectangle solid 7m by 8m by 4m?
7*8*4 = 224 cubic metres.
How do you find the area of 7m 4m 5m 3m?
To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
What triangle measures 2m 4m and 7m?
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
If a room is 7m by 4m and is 2.4m in height what is its volume in m3?
You simply multiply width x height x length so: 7 x 4 x 2.4 = 78.4 cubic meters the answer is 67.2 m3
How many triangles exist with the side lengths 4m 4m 7m?
The triangle with side lengths 4m, 4m, and 7m can exist because it satisfies the triangle inequality theorem. This theorem states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m > 7m holds true. Therefore, only one triangle can be formed with these side lengths.
How many triangles exist with the given side lengths 4m 4m 7m?
To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
How do you factor 6-7m-20m2?
-(4m + 3)(5m - 2)
How many triangles exist from the given lengths 4m 4m and 7m?
With side lengths of 4m, 4m, and 7m, only one triangle can be formed. This is an isosceles triangle, where two sides are equal (4m each) and the third side is different (7m). The triangle inequality theorem confirms that the sum of the lengths of any two sides must be greater than the length of the third side, which holds true in this case. Therefore, exactly one triangle exists with these lengths.
Can 4m 5m 7m side lengths form a Right triangle?
To determine if the side lengths of 4m, 5m, and 7m can form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the longest side (hypotenuse) equals the sum of the squares of the other two sides. Here, 7m is the longest side. Calculating, (4^2 + 5^2 = 16 + 25 = 41) and (7^2 = 49). Since (41 \neq 49), these side lengths cannot form a right triangle.
What is 4 over 7 minus 4 over m?
4/7 - 4/m need a common denominator--multiply the first term by m/m and the second by 7/7 4m/7m - 28/7m (4m-28)/7m OR 4/7 - 4/m
What is the value of m in 4m plus 3m equals 180?
4m + 3m = 180 7m = 180 m = 25 5/7
What is the area of 7m by 4m?
To find the area of a rectangle, you multiply the length by the width. In this case, the length is 7 meters and the width is 4 meters. Therefore, the area of a 7m by 4m rectangle is 28 square meters.
What is the volume of a rectangle solid 7m by 8m by 4m?
7*8*4 = 224 cubic metres.
The legs of a right triangle measure 7m and 9m what is the length of its hypotenuse to the nearest tenth of a meter?
The hypotenuse measures 11.4 meters in length.
How do you find the area of 7m 4m 5m 3m?
To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
What triangle measures 2m 4m and 7m?
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
