sqrt((4 x 4) + (7 x 7)) = sqrt(16 + 49) = sqrt 65 = 8.062m
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To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
7*8*4 = 224 cubic metres.
To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
You simply multiply width x height x length so: 7 x 4 x 2.4 = 78.4 cubic meters the answer is 67.2 m3
To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
-(4m + 3)(5m - 2)
4/7 - 4/m need a common denominator--multiply the first term by m/m and the second by 7/7 4m/7m - 28/7m (4m-28)/7m OR 4/7 - 4/m
4m + 3m = 180 7m = 180 m = 25 5/7
To find the area of a rectangle, you multiply the length by the width. In this case, the length is 7 meters and the width is 4 meters. Therefore, the area of a 7m by 4m rectangle is 28 square meters.
The hypotenuse measures 11.4 meters in length.
7*8*4 = 224 cubic metres.
Alright, darling, let's get this straight. First, we convert those pesky feet to meters because apparently, we can't just stick to one unit of measurement. 21ft is roughly 6.4m and 12ft is about 3.7m. Now, we multiply 6.4 by 3.7 to get a square meterage of around 23.68 square meters. Voila!
To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
well if you add it it is easy. A:11m.The above is a load of bovine droppings. P = 2(L + W) so the CORRECT answer is 22 m.The perimeter of a rectangle is 2 x (length + width).2 x (7m + 4m) = 2 x 11m = 22m
5m = 7 + 4msubtract 4m from both sides1m = 7m = 7=================================Oops. That first solution lost the '8' from the left side.An attempt to check the given equation with "m=7" fails.Try it like this:5m + 8 = 7 + 4mSubtract 4m from each side:m + 8 = 7Subtract 8 from each side:m = -1