The integral of sin x2 is one of the Fresnel Integrals.
It does not have a closed form solution. However, you can calculate a series solution by integrating the Taylor series, as follows:
The Taylor series expansion about x = 0 for sin x is
sin x = x - (x3/3!) + (x5/5!) - (x7/7!) +/- ...
Substitution of x2 for x yields
sinx2 = x2 - (x6/3!) + (x10/5!) - (x14/7!) +/- ...
Term-wise integration, using the power rule gives
{integral}sinx2 = (x3/3) - (x7/7*3!) + (x11/11*5!) - (x15/15*7!) +/- ...
This is the answer. It is the Fresnel Integral S(x).
There is a similar one for the integral of cos x2, called C(x).
It can be written in more compact form:
S(x) = (Sum from n = 1 to infinity) of (-1)n x4n+3/(4n+3)*(2n+1)!
It looks better in Sigma notation, with fractions, but
if you work out the first 4 terms, you will see agreement with the result for integrating the series expansion.
Here is a link to Fresnel Integral on Wikipedia:
http://en.wikipedia.org/wiki/Fresnel_integral
Thank you for posing this question.
Chat with our AI personalities
.5(x-sin(x)cos(x))+c
Integral of [1/(sin x cos x) dx] (substitute sin2 x + cos2 x for 1)= Integral of [(sin2 x + cos2 x)/(sin x cos x) dx]= Integral of [sin2 x/(sin x cos x) dx] + Integral of [cos2 x/(sin x cos x) dx]= Integral of (sin x/cos x dx) + Integral of (cos x/sin x dx)= Integral of tan x dx + Integral of cot x dx= ln |sec x| + ln |sin x| + C
-cotan(x)
22
Note that an angle should always be specified - for example, 1 - cos square x. Due to the Pythagorean formula, this can be simplified as sin square x. Note that sin square x is a shortcut of (sin x) squared.