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What else can I help you with?
Cos x sin x integral?
sin2x + c
Integral of sin square x times cos square x?
(1/8)(x-sin 4x)
What is the integral for sin 1-x?
- cos(1 - X) + C
What is the integral of cosine?
∫ cos(x) dx = -sin(x) + C
What is the integral of cosxsinx?
The integral of ( \cos x \sin x ) can be computed using a trigonometric identity. We use the identity ( \sin(2x) = 2 \sin x \cos x ), which allows us to rewrite the integral as: [ \int \cos x \sin x , dx = \frac{1}{2} \int \sin(2x) , dx. ] Integrating ( \sin(2x) ) gives: [ \frac{-1}{2} \cos(2x) + C, ] thus the final result is: [ \int \cos x \sin x , dx = \frac{-1}{4} \cos(2x) + C. ]
Integral of 1 divided by sinx cosx?
Integral of [1/(sin x cos x) dx] (substitute sin2 x + cos2 x for 1)= Integral of [(sin2 x + cos2 x)/(sin x cos x) dx]= Integral of [sin2 x/(sin x cos x) dx] + Integral of [cos2 x/(sin x cos x) dx]= Integral of (sin x/cos x dx) + Integral of (cos x/sin x dx)= Integral of tan x dx + Integral of cot x dx= ln |sec x| + ln |sin x| + C
Why sin integral is cos?
sin integral is -cos This is so because the derivative of cos x = -sin x
Integral of x cosx dx?
The integral of x cos(x) dx is cos(x) + x sin(x) + C
Cos x sin x integral?
sin2x + c
Integral of sin square x times cos square x?
(1/8)(x-sin 4x)
What is the integral for sin 1-x?
- cos(1 - X) + C
What is the integral of cosine?
∫ cos(x) dx = -sin(x) + C
What is the integral of cosxsinx?
The integral of ( \cos x \sin x ) can be computed using a trigonometric identity. We use the identity ( \sin(2x) = 2 \sin x \cos x ), which allows us to rewrite the integral as: [ \int \cos x \sin x , dx = \frac{1}{2} \int \sin(2x) , dx. ] Integrating ( \sin(2x) ) gives: [ \frac{-1}{2} \cos(2x) + C, ] thus the final result is: [ \int \cos x \sin x , dx = \frac{-1}{4} \cos(2x) + C. ]
Integral of sine squared x?
.5(x-sin(x)cos(x))+c
How you can defferentiate an integral?
If the upper limit is a function of x and the lower limit is a constant, you can differentiate an integral using the Fudamental Theorem of Calculus. For example you can integrate Integral of [1,x^2] sin(t) dt as: sin(x^2) d/dx (x^2) = sin(x^2) (2x) = 2x sin(x^2) The lower limit of integration is 1 ( a constant). The upper limit of integration is a function of x, here x^2. The function being integrated is sin(t)
What the integral of cotx?
∫ cot(x) dx is written as: ∫ cos(x) / sin(x) dx Let u = sin(x). Then, du = cos(x) dx, giving us: ∫ 1/u du So the integral of 1/u is ln|u|. So the answer is ln|sin(x)| + c
Integral of sin x sin 2x?
Ok, I know that sin 2x can be substituted out for 2 sin x cos x. so now I have the Integral of (sin x ) ( 2 sin x cos x ) dx which is 2 sin2x cos x dx If I use integration by parts with the u and dv, I find myself right back again..can you help. The book gives an answer, but I am not sure how it was achieved. the book gives 2/3 sin 2x cos x - 1/3 cos 2x sin x + C I may be making this more difficult than it is ? when you get the integral of 2 sin2x cos x dx use u substitution. u= sinx du= cosxdx. Then you'll get the integral of 2u^2 du.. .and then integrate...
