2 + ((6 + 2 * (n - 1) * (n - 1))
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
Well, honey, looks like we've got ourselves an arithmetic sequence here with a common difference of 7. So, to find the nth term, we use the formula a_n = a_1 + (n-1)d. Plug in the values a_1 = 12, d = 7, and n to get the nth term. Math doesn't have to be a drag, darling!
It depends what the next number in the sequence is. The simplest polynomial for those 5 terms is: U{n} = n² + 3n - 2
The given sequence is an arithmetic sequence with a common difference of 6, as each term increases by 6. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term a = 2, the common difference d = 6, and the term number n is not specified. Therefore, the nth term of the sequence 2, 8, 14, 20, 26 is 2 + (n-1)6.
Tn = 10 + n2
It is: nth term = 35-9n
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
Well, honey, looks like we've got ourselves an arithmetic sequence here with a common difference of 7. So, to find the nth term, we use the formula a_n = a_1 + (n-1)d. Plug in the values a_1 = 12, d = 7, and n to get the nth term. Math doesn't have to be a drag, darling!
The sequence S = 2, 2, 4, 6, 10, 16, 26, ... is the Fibonacci sequence multiplied by 2. Like the Fibonacci sequence, each term is found by adding the two previous terms, so Sn = Sn-1 + Sn-2.
To find the nth term of this sequence, we first need to determine the pattern or rule governing the sequence. By examining the differences between consecutive terms, we can see that the sequence is increasing by 9, 15, 21, 27, and so on. This indicates that the nth term is given by the formula n^2 + 1.
It depends what the next number in the sequence is. The simplest polynomial for those 5 terms is: U{n} = n² + 3n - 2
The given sequence is an arithmetic sequence with a common difference of 6, as each term increases by 6. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term a = 2, the common difference d = 6, and the term number n is not specified. Therefore, the nth term of the sequence 2, 8, 14, 20, 26 is 2 + (n-1)6.
Tn = 10 + n2
It is: nth term = 7n-9
t(n) = 10 - 6n where n = 1, 2, 3, ...
Well, isn't that just a lovely pattern we have here? Each term is increasing by 4, isn't that delightful? So, if we want to find the nth term, we can use the formula: nth term = first term + (n-1) * common difference. Just like painting a happy little tree, we can plug in the values and find the nth term with ease.
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