The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
n=n3. The numbers given in the question are equal to 13, 23, 33, 43, 53.
The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
58
18,23,28,33,... #1 is 18 #2 is 23 A difference of '5' Hence we can write '5n + x = 18 Where 'n' equals '1' Hence 5(1) + x = 18 5 + x = 18 Hence x = 18 - 5 = 13 So nth term is 5n + 13 NB Verification; does it work for the 4th term 5(4)+ 13 = 20 + 13 = 33 Which is true from above list.
All you have to do is add 5 each time(x+5) It's 43
x2-3=n
n=n3. The numbers given in the question are equal to 13, 23, 33, 43, 53.
28
The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)
44
It is increasing by 4 and the nth term is 4n+1