It is: 10n-7 and so the next term is 43
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
n=n3. The numbers given in the question are equal to 13, 23, 33, 43, 53.
nth term is 9n-3 and so the next term will be 42
The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
58
18,23,28,33,... #1 is 18 #2 is 23 A difference of '5' Hence we can write '5n + x = 18 Where 'n' equals '1' Hence 5(1) + x = 18 5 + x = 18 Hence x = 18 - 5 = 13 So nth term is 5n + 13 NB Verification; does it work for the 4th term 5(4)+ 13 = 20 + 13 = 33 Which is true from above list.
All you have to do is add 5 each time(x+5) It's 43
x2-3=n
n=n3. The numbers given in the question are equal to 13, 23, 33, 43, 53.
28
nth term is 9n-3 and so the next term will be 42
The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)
44