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What is the nth term for 5 11 17 23 29?
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
What is the nth term for 3 7 11 15?
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
What is the nth term 11 17 23 29?
It is 6n+5 and so the next term will be 35
What is the nth term of 20 29 38 47?
We note that there are a difference of '9' between terms . Hence '9n' Next find the constant 'c' 1st term ; 9(1) + c = 20 => c = 11 2 nd term ; 9(2) + c = 29 => c = 11 nth term is 9n + 11 e.g. 7th term is 9(7) + 11 = 63 + 11 = 74
What is the first 5 terms of the sequence with nth term 6n-1?
5, 11, 17, 23, 29
What is the nth term for 5 11 17 23 29?
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
What is the nth term for 3 7 11 15?
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
What is the formula for the nth term of this sequence 20 11 2 -7 -16?
Un = 29 - 9n
What is the nth term of the arithmetic sequence 22 15 8 1 ...?
The nth term is -7n+29 and so the next term will be -6
What is the nth term 11 17 23 29?
It is 6n+5 and so the next term will be 35
What is the nth term if the sequence is 22 15 8 1 -6?
It is: nth term = 29-7n
What is the nth term of 29-5n?
76
What is the nth term of 20 29 38 47?
We note that there are a difference of '9' between terms . Hence '9n' Next find the constant 'c' 1st term ; 9(1) + c = 20 => c = 11 2 nd term ; 9(2) + c = 29 => c = 11 nth term is 9n + 11 e.g. 7th term is 9(7) + 11 = 63 + 11 = 74
What is the first 5 terms of the sequence with nth term 6n-1?
5, 11, 17, 23, 29
What is the formula for the nth Term of these sequences 13 21 29 37 45 ...?
nth term = 5 +8n
What is the nth term for the sequence 5 15 29 47 69?
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
What is the nth term of 11, 17, 23, 29, 35?
n + 6 * * * * * I suggest you try t(n) = 6n + 5 instead.
