There are infinitely many polynomials of order 5 that will give these as the first five numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
One such is: U(n) = (5*n^5 - 15*n^4 + 85*n^3 - 201*n^2 + 250*n - 80)/8
another is U(n) = (4*n^5 - 80*n^4 + 340*n^3 - 900*n^2 + 1006*n - 330)/30
The simplest, based on a polynomial of order 1 is U(n) = 5 - 3n
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
It is: nth term = -4n+14
3n-2
You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6
The nth term is (2n - 12).
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
It is: nth term = -4n+14
3n-2
You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6
The nth term is (2n - 12).
The sequence 4, 6, 8, 10 is an arithmetic sequence where each term increases by 2. The nth term formula can be expressed as ( a_n = 4 + (n - 1) \cdot 2 ). Simplifying this gives ( a_n = 2n + 2 ). Thus, the nth term of the sequence is ( 2n + 2 ).
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
f = 10n + (n - 1)^2 For n=10 f = 10(10) + (10 - 1)^2 f = 181
1st term= 3 2nd term = 5 Nth term = 2n+1 10th term= 21 = 2(10)+1
1, 3, 6, 10, ... The nth term is n*(n+1)/2
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
The sequence 8, 6, 4, 2, 0 is an arithmetic sequence with a common difference of -2. The first term (a) is 8, and the common difference (d) is -2. The nth term can be expressed using the formula: ( T_n = a + (n-1)d ). Thus, the nth term is given by ( T_n = 8 + (n-1)(-2) = 10 - 2n ).