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There are infinitely many polynomials of order 5 that will give these as the first five numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
One such is: U(n) = (5*n^5 - 15*n^4 + 85*n^3 - 201*n^2 + 250*n - 80)/8
another is U(n) = (4*n^5 - 80*n^4 + 340*n^3 - 900*n^2 + 1006*n - 330)/30
The simplest, based on a polynomial of order 1 is U(n) = 5 - 3n
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What is the nth term for 26 18 10 2 -6?
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
What is the nth term for 10 6 2 -2?
It is: nth term = -4n+14
What is the nth term of 1 4 7 10 13?
3n-2
What is the nth term of -10 -8 -6 -4 -2?
The nth term is (2n - 12).
What is the nth term for 4 14 24 34?
You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6
What is the nth term for 26 18 10 2 -6?
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
What is the nth term for 10 6 2 -2?
It is: nth term = -4n+14
What is the nth term of 1 4 7 10 13?
3n-2
What is the nth term of -10 -8 -6 -4 -2?
The nth term is (2n - 12).
What is the nth term for 5 10 19 32 49 nth term?
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
What is the nth term for 4 14 24 34?
You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6
What is the nth term and the 10th term of the squence 10 21 34 49?
f = 10n + (n - 1)^2 For n=10 f = 10(10) + (10 - 1)^2 f = 181
What is the sequences in a triangular number?
1, 3, 6, 10, ... The nth term is n*(n+1)/2
What is the nth term of -8 2 12 22?
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
What is the nth term of 1 7 17 31 49?
2n^2-1
What is the nth term for 6 11 18 27 38?
The nth term of the sequence is (n + 1)2 + 2.
What is tenth term of the sequence 2n plus 1?
1st term= 3 2nd term = 5 Nth term = 2n+1 10th term= 21 = 2(10)+1
