It is probably 2n.
But there are infinitely many polynomials of degree 5, as well as other mathematical functions, that will fit the above 4 points.
For example, one possibility for the nth term is
Un = (n4 - 10n3 + 35n2 - 42n - 24)/4
The nth term is (2n - 12).
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
It is: nth term = -4n+14
The nth term is 2n So the 20th term is 2 x 20 = 40.
1 2 3 4= n 2 4 6 8 plusing two = 2n answer 2n
The nth term is (2n - 12).
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
The sequence 4, 6, 8, 10 is an arithmetic sequence where each term increases by 2. The nth term formula can be expressed as ( a_n = 4 + (n - 1) \cdot 2 ). Simplifying this gives ( a_n = 2n + 2 ). Thus, the nth term of the sequence is ( 2n + 2 ).
The given sequence is -2, -4, -6, which is an arithmetic sequence where each term decreases by 2. The first term (a) is -2, and the common difference (d) is -2. The nth term can be expressed using the formula ( a_n = a + (n-1)d ). Thus, the nth term is given by ( a_n = -2 + (n-1)(-2) = -2n ).
It is: nth term = -4n+14
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
The nth term is 2n So the 20th term is 2 x 20 = 40.
1 2 3 4= n 2 4 6 8 plusing two = 2n answer 2n
Ah, what a lovely sequence you have there! To find the nth term, you notice that each number is increasing by 2. So, if we start at 6, the nth term can be represented by the formula 2n + 4. Happy calculating, my friend!
To find the nth term of the sequence 4, 13, 28, 49, 76, we first identify the differences between consecutive terms: 9, 15, 21, 27. The second differences, which are constant at 6 (6, 6, 6), suggest that the sequence is quadratic. The nth term can be expressed as ( an^2 + bn + c ). By solving the equations based on the first few terms, we find the nth term is ( n^2 + 3n ).
The nth term of the sequence is (n + 1)2 + 2.
The nth term is 9n-2