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What else can I help you with?
What is the rule if 9 is the input and 7 is the output?
Subtract two.
If 4 is a input and 40 is the output and 7 is and input and 55 is the output and11 is and input and 75 is a output what is the rule?
Multiply by 5 and add 20 (or equivalently, add 4 and then multiply by 5)
Rule subtract 7 in 14 out is?
The "Rule subtract 7 in 14 out" refers to a specific mathematical or logical rule that involves taking an input, subtracting 7 from it, and then producing an output that is 14 more than the result of that subtraction. For example, if you start with a number ( x ), the output would be ( (x - 7) + 14 = x + 7 ). This means that the final output is effectively the original input increased by 7.
Why is multiplying the Input by 2 is the same as dividing the Output by 2?
It is not. Suppose the function is "add 7".Then an input of 1 gives an output of 1+7 = 8.Double the input to 2 and the output is 2+7 = 9Whereas simply halving the output gives 9/2 = 4.5So the question is based on false premises.
What is the number of inputs and outputs of a decoder that accepts 128 different input combinations?
A decoder that accepts 128 different input combinations requires 7 input lines, as (2^7 = 128). The number of output lines corresponds to the number of unique output combinations, which is also 128, since each input combination produces a distinct output. Therefore, the decoder will have 7 inputs and 128 outputs.
What is the rule if 9 is the input and 7 is the output?
Subtract two.
If 4 is a input and 40 is the output and 7 is and input and 55 is the output and11 is and input and 75 is a output what is the rule?
Multiply by 5 and add 20 (or equivalently, add 4 and then multiply by 5)
Rule subtract 7 in 14 out is?
The "Rule subtract 7 in 14 out" refers to a specific mathematical or logical rule that involves taking an input, subtracting 7 from it, and then producing an output that is 14 more than the result of that subtraction. For example, if you start with a number ( x ), the output would be ( (x - 7) + 14 = x + 7 ). This means that the final output is effectively the original input increased by 7.
A picture of a input and output machine in math?
if one answer is 6 and the other answer is 7, how do the output numbers from the input/output machines compare
Why is multiplying the Input by 2 is the same as dividing the Output by 2?
It is not. Suppose the function is "add 7".Then an input of 1 gives an output of 1+7 = 8.Double the input to 2 and the output is 2+7 = 9Whereas simply halving the output gives 9/2 = 4.5So the question is based on false premises.
What is the rule for input 4 out 11?
the rule is add 7 because 4 plus 7 = 11
Is remote control an input or output device?
you really have been waiting around 7 years I believe I got the answer I think its a input device I'm sorry you had to wait around 7 years
What is the number of inputs and outputs of a decoder that accepts 128 different input combinations?
A decoder that accepts 128 different input combinations requires 7 input lines, as (2^7 = 128). The number of output lines corresponds to the number of unique output combinations, which is also 128, since each input combination produces a distinct output. Therefore, the decoder will have 7 inputs and 128 outputs.
What is the rule for Input 456712 Output 0246?
There are many rules for that pair. Without further information about the kind of operators expected to be used it is impossible to give an answer. Let me give you a very simple example: What is the rule for input 2 output 4: rule 1: x → x + 2 rule 2: x → 2x rule 3: x → x^2 rule 4: x → x^3 ÷ 2 rule 5: x → x^3 - x^2 rule 6: x → x^3 - 2x rule 7: x → x^3 - 4 rule 6: x → x^4 - x^3 - x^2 etc Even with a list of permissible operators, there is no one definite answer given only one pair of input/output - it would require further examples of inputs and their corresponding outputs to be able to narow the possible answers: only slightly as it is still possible to find [infinitely] many polynomials that provide the given input/output pairs.
What is the VHDL programme for 8 to 3 priority encoder using data flow style?
A VHDL program for an 8-to-3 priority encoder using data flow style can be implemented using the when-else construct. The encoder outputs a 3-bit binary representation of the highest-priority active input (from 7 to 0), while also providing an output for invalid conditions. Here’s a simple example: library IEEE; use IEEE.STD_LOGIC_1164.ALL; use IEEE.STD_LOGIC_ARITH.ALL; use IEEE.STD_LOGIC_UNSIGNED.ALL; entity priority_encoder is Port ( input : in STD_LOGIC_VECTOR(7 downto 0); output : out STD_LOGIC_VECTOR(2 downto 0); valid : out STD_LOGIC); end priority_encoder; architecture dataflow of priority_encoder is begin process(input) begin case input is when "00000000" => output <= "000"; valid <= '0'; when others => output <= "111"; -- Default output for higher priority valid <= '1'; if input(7) = '1' then output <= "111"; elsif input(6) = '1' then output <= "110"; elsif input(5) = '1' then output <= "101"; elsif input(4) = '1' then output <= "100"; elsif input(3) = '1' then output <= "011"; elsif input(2) = '1' then output <= "010"; elsif input(1) = '1' then output <= "001"; elsif input(0) = '1' then output <= "000"; end if; end case; end process; end dataflow; This code checks the input vector and determines the highest active bit, setting the output accordingly.
Does CD4026 is the same ic for CD4033?
Both the CD4026 and CD4033 are BCD to 7 Segment counter/decoders. The 4026 has a display enable input/output, while the 4033 has a ripple blanking input/output.
What output is the sum of 2 times the input 3 and 4?
3 + 4 = 7 7 x 2 = 14
