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If the question is about the slope of the line joining (-4, -2) and (0, 4), the answer is:
slope = [4 - (-2)]/[0 - (-4)] = 6/4 = 3/2
m(slope = Y2 - Y1/X2 - X1(0, 4) and (4, - 2)m = - 2 - 4/4 - 0= - 6/4= - 3/2======
The slope of the line joining the two pints is (4 - 2)/(-3 - 0) = -2/3 Therefore the slope of the perpendicular is 3/2
Points: (-6, 0) and (2, 4) Slope: (0-4)/(-6-2) = 1/2
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It is: (5-4)/(2-0) = 1/2
Points: (0, -1) and (-2, -4)Slope: 3/2
Points: (3, -2) and (0, 4) Slope: -2
If you mean points of (-2, 2) and (0, 4) then the slope works out as 1
Points: (-2, -3) and (4, 0) Slope: (-3-0)/(-2-4) = 1/2
Points: (5, 0) and (3, -4) Slope: 2
Slope = (8 - 0)/(0 - 4) = -2
slope = change_in_y / change_in_x = (2 - -4) / (3 - 0) = 6/3 = 2
Slope: (2-4)/(0--3) = -2/3 Perpendicular slope: 3/2
The slope of points 4 5 and -2 0 would be about 5/6.
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
m(slope = Y2 - Y1/X2 - X1(0, 4) and (4, - 2)m = - 2 - 4/4 - 0= - 6/4= - 3/2======
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