x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
3
x2 - x = 20 x = 5
x2 + x2 = 2x2
X2 - X - 6 = 0what two factors of - 6 add up to - 1 ?(X + 2)(X - 3)============(- 2, 0 ) and (3, 0 )------------------------------solution set of points
x = { +6, -6 }
x2 + 49 = 0 ∴ x2 = -49 ∴ x = 7i
Using the quadratic formula, I found the solution set is x=2,x=-9
x2≤64
-4 and 4
x2=20x 0 is an obvious solution if x is not 0, then divide both side by x, so x=20 so the solutions are 0 and 20
do it yourself
(-4,6)
-4
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
There is no one solution to this problem. For example: y = x2 y = 5x y = x + 20 y = 2x / 5 + 23 These are just four of the infinite set functions that would give "y" a value of 25 when x = 5.
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)