Why, that's just 6 times the sum of the numbers from 1 to 50 !
The sum of the numbers from 1 to 50 is:
1 + 50 = 51
2 + 49 = 51
3 + 48 = 51
4 + 47 = 51
5 + 46 = 51
.
.
.
etc. There are 25 pairs, and each pair sums to 51. So the sum of 1 ... 50 is (25 x 51) = 1,275.
The sum of the first 50 multiples of 6 is (1,275 x 6) = 7,650.
The first 50 multiples of 6 are the first fifty even multiples of 3.
90
It is: 6+12+18 = 36
25, 50, 75, 100, 125, 150
To find the multiples of 6 between 50 and 70, we first need to determine the multiples of 6. Multiples of 6 include 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, and 72. However, we are only interested in the multiples that fall between 50 and 70. Therefore, the multiples of 6 that fall between 50 and 70 are 54 and 60.
5 + 10+15+20=50 ans
The first 50 multiples of 6 are the first fifty even multiples of 3.
90
It is: 6+12+18 = 36
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
6+12+18+24+30=90
6 + 12 + 18 + 24 + 30 + 36 = 126
The first 6 multiples of 9 are 9, 18, 27, 36, 45 and 54. Their sum (total) is 189. In other words, 1x9 + 2x9 + 3x9 + 4x9 + 5x9 + 6x9 = 21x9 = 189.
It is 751500.Here's the first ten.6, 12, 18, 24, 30, 36, 42, 48, 54, 60
6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90.
25, 50, 75, 100, 125, 150