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Why, that's just 6 times the sum of the numbers from 1 to 50 !
The sum of the numbers from 1 to 50 is:
1 + 50 = 51
2 + 49 = 51
3 + 48 = 51
4 + 47 = 51
5 + 46 = 51
.
.
.
etc. There are 25 pairs, and each pair sums to 51. So the sum of 1 ... 50 is (25 x 51) = 1,275.
The sum of the first 50 multiples of 6 is (1,275 x 6) = 7,650.
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How do you find the first 50 even multiples of 3?
The first 50 multiples of 6 are the first fifty even multiples of 3.
What is the sum of the first 5 multiples of 6?
90
What is the sum of the first three multiples of 6?
It is: 6+12+18 = 36
What are the first 6 multiples of 25?
25, 50, 75, 100, 125, 150
What multiples of 6 fall between the numbers 50 and 70?
To find the multiples of 6 between 50 and 70, we first need to determine the multiples of 6. Multiples of 6 include 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, and 72. However, we are only interested in the multiples that fall between 50 and 70. Therefore, the multiples of 6 that fall between 50 and 70 are 54 and 60.
What is the sum of the first 4 multiples of 5?
5 + 10+15+20=50 ans
How do you find the first 50 even multiples of 3?
The first 50 multiples of 6 are the first fifty even multiples of 3.
What is the sum of the first 5 multiples of 6?
90
What is the sum of the first three multiples of 6?
It is: 6+12+18 = 36
What is the sum of the first 4 multiples of 6?
To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
The sum of three consecutive multiples of 6 is 666find the multiples?
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
What is the sum of the first 2 multiples of 6?
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
What is the sum of the first five multiples of 6?
6+12+18+24+30=90
What is the sum of the first 6 multiples of 9?
The first 6 multiples of 9 are 9, 18, 27, 36, 45 and 54. Their sum (total) is 189. In other words, 1x9 + 2x9 + 3x9 + 4x9 + 5x9 + 6x9 = 21x9 = 189.
What is the sum of the first 500 multiples of 6?
It is 751500.Here's the first ten.6, 12, 18, 24, 30, 36, 42, 48, 54, 60
What is the sum of first 15 multiples of 6?
6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90.
What are the first 6 multiples of 25?
25, 50, 75, 100, 125, 150
